Get exact object which contains part of string from another array

JavaScript
1

Hi :),
I want to return an object which contains a part of a string from an array.
const array = ['UK', 'Germany', 'Sweden'];
const object = {text: "Stockton-on-Tees, UK"}

If the object.text contains part of string e.g ‘UK’ , I want to return that object {text: "Stockton-on-Tees, UK"}

Thank you for your time.

2

Be careful here.

Is Kirkuk, Iraq meant to be returned? Look closely…

3

Yes, exactly :slight_smile:

4

So…
object.text is the element to check.
Array.some() to quickly walk the array and return a boolean.
String.includes() is your test.

Give it a go yourself, see what you come up with.

5

I have tried this already:
array.some((el) => object.text.includes(el))
I’m getting boolean not the object.
So I need to find a different solution.

6

If the boolean is true, return the object. If it is false, return… whatever it is you want to return if it didn’t match.

7

With one object will be ok, but if I get 10 objects I want to return only those which contains the string.

8

You want to Array.filter() the array of objects, then, using the test you’ve already written to evaluate.

9

Ok, like this?

array.filter((el) => object.text.includes(el))

Then I’m getting value from an array, not object.

["UK"]
10

Not quite.

const array = ['UK', 'Germany', 'Sweden'];
const objects = [{text: "Stockton-on-Tees, UK"},{text: "Atlanta, GA, US"}]

Filter the objects, such that each object is evaluated by array.some((el) => object.text.includes(el))

1 Like
11

I’m not sure if you understand what I want to achieve. (Maybe my description is lack of sense)
I find the solution by changing the object to array and iterate it.

[object].filter((obj) =>
array.map((el) => el.includes(obj.text))
);
12

I don’t… quite think that works, but… you tell me.

const object = {text: "NotAPlace"}

13

Thank you for your advice and help!
I want to display an object which contains even part of a string which is common in the array, in this example ‘UK’, so the algorithm should return the {text: "Stockton-on-Tees, UK"}

14

asked and answered.

15

It seems that we are wanting to retrieve an object that matches the given country. We can use map to achieve that.

const array = ['UK', 'Germany', 'Sweden'];
const locations = array.map(function findLocation(country) {

});

There can be several objects, so we use an objects array to store them all.

const objects = [
    {text: "Stockton-on-Tees, UK"},
    {text: "Twilight Hawker's Market, Perth, Australia"},
    {text: "Weihnachtsmarkt Am Kölner Dom, Cologne, Germany"}
];

In the map I want to find the first object that matches my requirements:

const array = ['UK', 'Germany', 'Sweden'];
const locations = array.map(function findLocation(country) {
    return objects.find(function includesCountry(object) {
    
    });
});

and that requirement is where the object text matches the country.

const array = ['UK', 'Germany', 'Sweden'];
const locations = array.map(function findLocation(country) {
    return objects.find(function includesCountry(object) {
        return object.text.includes(country);
    });
});

You end up with the locations array having three items, the first two are objects because they matched, and the last one is appropriately undefined.

[
    {text: "Stockton-on-Tees, UK"},
    {text: "Weihnachtsmarkt Am Kölner Dom, Cologne, Germany"},
    undefined
]
1 Like
16

I resolved it by myself. Please remove it.

17

Why not post how you solved it? It could possibly be of some help to someone in the future…

3 Likes
18

Of course.

[object].filter((obj) =>
array.map((el) => el.includes(obj.text))
);
3 Likes
19

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