Fire Event on Second Attempt

JavaScript
1

I am making a backspace function, but I only want the event to fire if the input field is empty and I hit backspace again. I don’t want it to fire when I hit backspace and the field is empty simultaneously!

If I type in… j then hit backspace, my event will fire.

I want to type in… j then hit backspace, don’t fire the event, hit backspace again, fire the event


function backspace_delete(e) 
{
	if (!e) 
	{ 
		// IE reports window.event instead of the argument
		e = window.event;
	}
	var keycode;
	
	if (document.all) 
	{
		// IE
		keycode = e.keyCode;
	} 
	else 
	{
		// Not IE
		keycode = e.which;
	}
	
	if (keycode == 8 && with_field.value == '')
	 {
		if (document.all)
		{
			//IE
			removeElementById(with_input.lastChild.id);
		} 
		else 
		{
			//Non IE
			removeElementById(with_input.lastChild.id);
		}
	}
}
2

Sorry not understanding what you are requiring.

You have an input field (type=“text”). Say it starts empty.

You type in the three letters “abc” and then backspace. You want nothing to happen.

You hit backspace a second time and the letter “c” is removed.

You hit backspace a third time and the letter “b” is removed.

Your type the letter “d” and then backspace. You want nothing to happen.

You hit backspace a second time and the letter “d” is removed.

You hit backspace a third time and the letter “a” is removed. Leaving the field empty.

You hit backspace a fourth time. Nothing can happen so nothing does.

In this scenario you could achieve the desired effect by everytime a character a,b,c,d, … is typed setting a property, of you choice - say ignorebs, of the input element to true. If a backspace is detected and the property is true you ignore the keystroke and set the property to false so next time the backspace will action.