Warning: in_array() - Wrong datatype for second argument

PHP
1

Hello,

I am trying to check that all my fields in my form have value when submited. So instead of using isset i am using in_array, but get an error (Wrong datatype for second argument)

can anyone help



$form = array('FirstName', 'LastName', 'EmailAddress', 'YourBorough');
	
	foreach($_POST as $key => $value){
		if(in_array($value, $from)){
				echo 'all fields filled in';						
		}

thanks

2

Is it because it says from rather than form? :stuck_out_tongue:

3

it is because whole algorithm is wrong.

4

ha lol thats true thanks for spotting that. On another note, i am trying to see if my posted form has all fields filled in, but it looks like in_array is not what i should use as it’s not checking if it set (like isset)? any ideas? i dont want to check each individual field if its set or not, but would to use a loop.

5 

$invalidField = false;
foreach ($fields as $fieldName) {
    if (!isset($_POST[$fieldName]) || strlen($_POST[$fieldName]) == 0) {
        $invalidField = true;
        break;
    }
}

Alternatively, make an $invalidFields array and when a bad field is found, put the field name into the array. Now you can tell the user exactly which fields were missing.

6

ok well this seems to do it as well eventough it very primitive:


foreach($_POST as $key => $value){
				
		if(empty($value) || strstr("void", $value)){
				echo '123';						
		}
7

thanks very much dude your solution is better then the one i came up with :slight_smile:

8

Yes.
Such situation may never occur if ma201dq had used:

error_reporting(E_ALL);
ini_set('display_errors', true);
9

Or better:


error_reporting(-1);
ini_set('display_errors', 1);

-1 will catch all possible errors including E_STRICT, E_DEPRECATED etc. and those errors might go to E_ALL in php 6, so catch it now and your code will be compatible with future versions of php.