No I think you have misunderstood what I’m asking about here I’ve used $2<em>$1</em> in the above code but I’m asking how would it be different if I used \2<em>\1</em> instead? I see no obvious difference between them and they both “apparently” seem to be the same…
replacement may contain references of the form \\n or $n, with the latter form being the preferred one.
I’m guessing the backslash way is like a “go get it” and the dollar sign way is more like a “use what’s already in memory”. In other words, though the end result is the same the latter is more efficient.