Session passing over to a next page in PHP7

PHP
1

I have the code below at a page.

<?php

$myDomain='myDomain.com';
session_set_cookie_params(0, '/', '.' . $myDomain.'');
session_start();

if ( isset($_SESSION['mySession']) ) {

echo 'mySession is already set';

} else {

echo 'mySession will be set';
$_SESSION['mySession']=1;

}

If I open the page for the first time, it says, “mySession will be set”.
and I open the page again, it says “mySession is already set”.
So far so good.
But it is in the PHP5.

I have another server which is in the PHP7.
Same code is in the PHP7.

Whenever I open the page, it continuously says “mySession will be set”.
Although “mySession” is set, it seems not pass over to the next openning.

How can I make “mySession” pass over to a next page?

2

I’ve got a local PHP 7.2 server with php -S localhost:8080 running, works as expected.

3

My php is also 7.2.

Do you mean it says “mySession is already set” from the 2nd time if you run the code above?

4

Try adding the following and see if errors or warnings are generated:

<?php 
declare(strict_types=1);
errot_reporting(-1);
ini_set('display_errors', '1');

session_start();
//
5 
<?php

declare(strict_types=1);
errot_reporting(-1);
ini_set('display_errors', '1');

$myDomain='myDomain.com';
session_set_cookie_params(0, '/', '.' . $myDomain.'');
session_start();

if ( isset($_SESSION['mySession']) ) {

echo 'mySession is already set';

} else {

echo 'mySession will be set';
$_SESSION['mySession']=1;

The code above says " Fatal error : Uncaught Error: Call to undefined function errot_reporting() on line 4

I try to remove the code below form the original code.

$myDomain='myDomain.com';
session_set_cookie_params(0, '/', '.' . $myDomain.'');

And make the code below. And it works fine.

<?php

session_start();

if ( isset($_SESSION['mySession']) ) {

echo 'mySession is already set';

} else {

echo 'mySession will be set';
$_SESSION['mySession']=1;

}

As the code above works fine, I can think the code below is the problem.

$myDomain='myDomain.com';
session_set_cookie_params(0, '/', '.' . $myDomain.'');

I added the problem code above for sub-domains.
In order to make the sessions and cookies works as same to all sub-domains of myDomain.com, for example, sub1.myDomain.com, sub2.myDomain.com.

With the problem code above, a session or cookie work not only myDomain.com but also sub1.myDomain.com and sub2.myDomain.com in PHP5.
But it doesn’t work as I expected in PHP7.

Can I make it work with cross-domain in PHP7

6

Maybe error_reporting(-1) :biggrin:

1 Like
7

I cannot edit this.
I guess it’s because of time passing.

I modify the quote above like the following.

8

The code1 below says " Fatal error : Uncaught Error: Call to undefined function errot_reporting() in sessionTest:4 Stack trace: #0 {main} thrown on line 4
code1

<?php

declare(strict_types=1);
errot_reporting(-1);
ini_set('display_errors', '1');

$myDomain='myDomain.com';
session_set_cookie_params(0, '/', '.' . $myDomain.'');
session_start();

if ( isset($_SESSION['mySession']) ) {

echo 'mySession is already set';

} else {

echo 'mySession will be set';
$_SESSION['mySession']=1;

And the code2 below which is without the semicolon(:wink: says " Parse error : syntax error, unexpected ‘ini_set’ (T_STRING) in sessionTest.php on line 5
code2

<?php

declare(strict_types=1);
errot_reporting(-1)
ini_set('display_errors', '1');

$myDomain='myDomain.com';
session_set_cookie_params(0, '/', '.' . $myDomain.'');
session_start();

if ( isset($_SESSION['mySession']) ) {

echo 'mySession is already set';

} else {

echo 'mySession will be set';
$_SESSION['mySession']=1;

How can I remove the Fatal error or Parse error?

9

Try @Gandalf’s solution In a previous post.

The syntax was not validated and typed incorrectly on my iPad.

10

Do you mean the code1 below should be modified to the code2 below?
code1

declare(strict_types=1);
errot_reporting(-1);
ini_set('display_errors', '1');

code2

declare(strict_types=1);
errot_reporting(-1)
ini_set('display_errors', '1');
11

I guess this part below has possibly incorrect.

session_set_cookie_params(0, '/', '.' . $myDomain.'');
12

Read post #6

13

Thank you.
I am afraid I made typo there.

So the code below is correcting the typo.

<?php

declare(strict_types=1);
error_reporting(-1);

ini_set('display_errors', '1');

$myDomain='dot.kr';
session_set_cookie_params(0, '/', '.' . $myDomain.'');
session_start();

if ( isset($_SESSION['mySession']) ) {

echo 'mySession is already set';

} else {

echo 'mySession will be set';
$_SESSION['mySession']=1;

It says “mySession will be set” continuously.
It means the session doesn’t pass over to the next page.

How can I make it the session pass over to the next page?
How can I see the quote below as the result?

14

Is the code actually running at dot.kr, or somewhere else? (like localhost)

Also, this:

$myDomain='dot.kr';
session_set_cookie_params(0, '/', '.' . $myDomain.'');

is a lot harder to understand than this:

session_set_cookie_params(0, '/', '.dot.kr');
15

The code below works fine, I can see “mySession is already set”
Thank you, rpkamp.

<?php

declare(strict_types=1);
error_reporting(-1);

ini_set('display_errors', '1');

session_set_cookie_params(0, '/', '.dot.kr');
session_start();

if ( isset($_SESSION['mySession']) ) {

echo 'mySession is already set';

} else {

echo 'mySession will be set';
$_SESSION['mySession']=1;
}

By the way, dot.kr is activated when I test it

When I test it, the server connected to real IP.
But mostly the server is connected to a router for internet connection.
That is one reason why my test is so slow.

The 3 code below don’t work correctly.

session_set_cookie_params(0, '/', '.localhost');
session_set_cookie_params(0, '/', '.127.0.0.1');
session_set_cookie_params(0, '/', '.218.160.156.29');

The code below works fine.

session_set_cookie_params(0, '/', '.dot.kr');

I think I have to find a way “dot.kr” is always activated,

16

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