"Return" not working

JavaScript
1

Hi,

I am using this code:

function findcustid(custid) {
    var custid = custid;
    alert (custid);
}

But this opens a dialogue window showing the value of (custid). I need to store this information and using it later to define the value of a variable later on in the Javascript. I tried replacing “alert” with “return” but then it does not work. For your information, the var is a single value not an multiple value array.

Thanks,

Matt.

2

Hi @MatthewBOnline,

I’m a little confused about what you’re trying to do here. Where does the value of custid come from? Are you trying to prompt the user to input this value?

3

Yes - they choose from a drop down menu in a form - I am using AJAX Java to avoid using a submit button.

The code is this:

---select name="report_type" onchange="findcustid(this.options[this.selectedIndex].value);"

option value=“customerone”>cust 1</option
option value=“customertwo”>cust 2</option
option value=“customerthree”>cust 3</option
—​​​
The values must be letter not numbers in the case i am using it for.

it is a form above but my code would not paste in very easily

4

Remove the var before custid inside the function, creating a value for a variable that is undeclared gives it global scope.

5

or remove the parenthesis around (custid) if you want to use return, then test calling the value of custid by using findcustid() without parameters.

6

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