Printing errors in a list

PHP
1

I currently use the following function to print error messages if any are generated:


function print_error($key, $errors) {
if (isset($errors[$key])) {
print "<li>{$errors[$key]}</li>"; }
}

Above the form that is being processed, I have:


<ol class="checklist errors">
...error messages are inserted here in list items...
</ol>

The errors are printed inside that OL by:


<?php print_error('message', $errors) ?>
<?php print_error('name', $errors) ?>
et cetera...

My question is how do I print the ordered list only when errors are generated, so that the HTML does not need to have an empty list in it?

2

Before calling print you can check if there are any errors in array


<?php
if(count($errors) > 0)
{
?>
 <ol>
      <?php foreach($errors as $key => $value)
      {
         print_error($key, $errors);
       } ?>
  </ol>
<?php
}

simple enough, isn’t it.

3

simple enough, isn’t it.

Not really. Where does the last php tag close? And which part of my code does this example replace?