Oracle - subtracting 2 hours from date returned

I am trying to write a query that will check

where row_date >= sysdate - 2 hours

what would the syntax look like for this?
do i need to set the date format each time i run the query?

thanks.

Not sure (I don’t use Oracle), but if row_date is a date type in Oracle, you could try something like:

SELECT *
FROM tablename
WHERE row_date >= SYSDATE-2/24

Otherwise, if it is a char type, you would want something like:

SELECT *
FROM tablename
WHERE TO_DATE(row_date, ‘DD-MON-YY’) >= SYSDATE-2/24

Hope that helps!

– Jill

where row_date >= sysdate - interval ‘2’ hour

i know it looks weird having that 2 in quotes, but that’s the format

Good thing I don’t use Oracle, eh?!

THAT’s the command I was searching around for…didn’t have my Oracle Bible with me, though. :frowning:

Just for curiosity’s sake, what is the difference between the SYSDATE - 2/24 versus the SYSDATE - interval ‘2’ hour ?

Everything I’ve researched has show the SYSDATE - 2/24…

that’s a really good question

i trust the interval arithmetic expression to give the correct time, whereas sysdate-2/24 is a date minus a fraction, and who knows if that will come up with the same datetime result

i wish i had oracle, this would be such a simple test to run…

Thank you both for the feedback…i appreciate it

mike

i don’t have any oracle books, i just use their online docs

:cool:

You must have better luck than me. I have the worst time trying to navigate through those docs…it’s usually just faster to pull the book out.

do you have a technet id?

Oracle8i SQL Reference

works for me