Omitting an array member

[designtrooper]

Imagine that you have to pass an array from a foreach loop but omitting the first array member.

How can I do it?
One thought I made was to remove the array member before the loop and add it again after the loop ends.

What do you propose?

[Dormilich]

I’d go for array_slice() since it doesn’t modify the original array.

[droopsnoot]

Not quite sure I understand the question, but would something like this do it?

$flag = false
foreach ($array as $ix => $row) { 
  if ($flag == false) {
    $flag = true;
    }
  else {
    // do whatever you want with $ix and $row
  }
}

so it doesn’t do the action the first time through.

[Dormilich]

That’s possible, but it needs to execute the if condition for each item.

[designtrooper]

thiis seems to be OK…I will try it.

[Mittineague]

If it’s always and ever only the first, maybe you could “shift” it off the array?

http://php.net/manual/en/function.array-shift.php

[Dormilich]

That was @designtrooper’s first idea, although to work properly (more in terms of best practices) that implies that the foreach() is called in another function (or on a copy of the array), so the original array doesn’t get modified.