this is my select field in form
<select class="form-control" id="fruits" name="fruits" type="text">
<option value = '0'>-Select-</option>
<option value = '1'>Apple</option>
<option value = '2'>Orange</option>
This is how I am trying to get the values
$conn = mysqli_connect("localhost", "root", ""); // Establishing Connection with Server..
$db = mysqli_select_db($conn,"basket");
$list= mysqli_query($conn,"SELECT fruits from tbl_shop_A");
$row = $list->fetch_object()
// display names but as the values are storing in databse as option values they are displaying in table also as option value
<th><?php echo $row->fruits; ?></th>
<th> 2 </th>
The values are storing in database as option values i.e 1, 2
- but I want to display it in table according to their names i.e. orange , apple
How to do that ?
Well, ask yourself this - why are you giving them values of 0,1,2?
Also there’s no way you’re calling this line:
$row = mysqli_query($conn,"SELECT fruits from tbl_shop_A");
followed by this one
<php echo $row->medium; ?>;
because you haven’t selected anything called ‘medium’ in your query. Also $row isnt a row. It’s the query result. You’ll have to get your values out of it (fetch, fetch_array, etc) somehow.
So show us the actual code you’re trying to debug.
hey Sorry for the mistake now I have updated my code please guide me through it
I see form HTML and the SELECT query code. If the SELECT is returning numeric values from the “fruits” field of the “tbl_shop_A” table it suggests that field contains numeric values.
What has not been shown is how the value attribute values from the
<option> elements are getting into those table fields.
Can you post the code related to the INSERT (and UPDATE if there is one) query?
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