How to pass a random string into another variable

PHP
1

I have two scripts. One is a tinyurl API and the other gnerates random strings. What I want to do it pass a random string into the tiny URL API script such that the tiny URL generated is always different

<?php

function createRandomPassword() { 

    $chars = "abcdefghijkmnopqrstuvwxyz023456789"; 
    srand((double)microtime()*1000000); 
    $i = 0; 
    $pass = '' ; 

    while ($i <= 7) { 
        $num = rand() % 33; 
        $tmp = substr($chars, $num, 1); 
        $pass = $pass . $tmp; 
        $i++; 
    } 

    return $pass; 

} 

// Usage 
$password = createRandomPassword(); 

?>


<?php


//gets the data from a URL  
function get_tiny_url($url)  
{  
	$ch = curl_init();  
	$timeout = 5;  
	curl_setopt($ch,CURLOPT_URL,'http://tinyurl.com/api-create.php?url='.$url);  
	curl_setopt($ch,CURLOPT_RETURNTRANSFER,1);  
	curl_setopt($ch,CURLOPT_CONNECTTIMEOUT,$timeout);  
	$data = curl_exec($ch);  
	curl_close($ch);  
	return $data;  
}

//test it out!
$new_url = get_tiny_url('http://domain.com/?password);


echo $new_url

?>

where it says http://domain.com/?password i want the password value in the first script to be passed before a tiny url is generated

thanks

2

missing the identifier.

3

As an aside: you should be taking modulus 35 on your random number, not 33. Taking mod 33 leaves you never using 8 or 9.

4

$new_url = get_tiny_url(“http://domain.com/?pass=”.$password);

and then $_GET[‘pass’] will identify the script called in the index file.

5 

$new_url = get_tiny_url('http://domain.com/?' . $password);
6

What do you mean? I am missing identifier? I just corrected if OP was supposed to echo generated random text in the URL and he missed a $ sign from the $password variable.