How to create a button within $.ajax() Function()? can't created.. Plz help me

JavaScript
1 
<!DOCTYPE html>
<html>
<head>
 <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script> 
 <script type="text/javascript">  
  $(function() {
  
    bind123();
   
  
  });

    
function bind123()
 {  
  $.ajax({
    success: function() {
    alert('WELCOME');

  var $input = $('<input type="button" value="new button" />');
  $input.appendTo($("body")); 

  var x = '<input type="button" id="actionbtn123" class="btn btn-success form-control" value="Add Details"  />';
  return [x].join(''); 
  
    }
  
    });
 }   
 </script>
</head>
<body>
</body>
</html>
2

you never send off the AJAX call (missing URL).

3

write down the right method

4

Plenty of good examples are given at http://api.jquery.com/jquery.ajax/#entry-examples

5

This topic was automatically closed 91 days after the last reply. New replies are no longer allowed.