Hi,
I’m using the following code to grab a csv file from one website & keep it on my website. The code is working fine.
<?php
$url = 'http://thewebsite.com/export.aspx?type=csv&report=nameofthereport~8~';
$path = '/home/path/to/mywebsite.com/public_ftp/incoming/nameofthereport_Area_8.csv';
$fp = fopen($path, 'w');
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_FILE, $fp);
$data = curl_exec($ch);
curl_close($ch);
fclose($fp);
?>
Here’s what I want to do next. I want to query a database, and replace nameofthereport and 8 with the results of the query. So the main idea is to grab multiple csv files of different names from the same website.
The difference in the file names are reflected in the $report and $district variable (referring to the code snippet below). For example, I want to grab the following files:-
http://thewebsite.com/export.aspx?type=csv&report=salesreport~1~
http://thewebsite.com/export.aspx?type=csv&report=employeereport~2~
http://thewebsite.com/export.aspx?type=csv&report=productionreport~3~
From the above example, salesreport, employeereport and productionreport are stored in the report column of the database. 1,2,3 are stored in the district column of the database.
My code to query the database is below.
<?php
include("/home/path/to/mywebsite.com/public_html/db_connect.php"); //connect to the database
$today = date('Y-m-d');
$query1=("SELECT * FROM `table_name` WHERE expiry > $today");
$result1=mysqli_query($GLOBALS["___mysqli_ston"], $query1);
$num1=mysqli_num_rows($result1);
if ($num1 > 0) {
while ($data = mysqli_fetch_array($result1)){
$email_to = $data["email"];
$district = $data["district"];
$report = $data["report"];
}
}
?>
Based on the code above, I would like to replace nameofthereport with $report and 8 with $district
Could you show me how to put the first code snippet ‘into’ the second code snippet so that it loops properly?
Thanks.