Do I need a Call Back Function?

JavaScript
1

I’m running… but console.log(ajax_call(info)); keeps being displayed as undefined.


function autosuggest_results (info){				
	if (info.length > 1)
	{		
		var with_field		= document.getElementById('users');
		var with_auto_id	= document.getElementById('with_auto');
		var search_emp_id	= document.getElementById('search_employees');
		var users_list		= document.getElementsByName('with_uid[]');
		
		if(with_auto_id){
			var with_auto		= with_auto_id;
		}else{
			var with_auto		= search_emp_id;
		}
		
		ajax_call(info);
		
		console.log(ajax_call(info));
		
	}
	else
	{
		hide();
	}
}

function ajax_call(info){
	var with_u_list = prev_picked();
	
	ajax.get('/assets/ajax/associates_search.php?info=' + info + '&sid=' + hex_md5(sess_id()) + '&list=' + with_u_list, function(resp)
	{		
		var search 	= eval('(' + resp + ')');
		
		show();
		
		var with_auto_id	= document.getElementById('with_auto');
		var search_emp_id	= document.getElementById('search_employees');
		
		if(with_auto_id){
			var with_auto		= with_auto_id;
		}else{
			var with_auto		= search_emp_id;
		}
		
		if(search.length > 0){
			fill_list(search);
		}else{
			removeChildren(with_auto);
			
			var no_res_div = document.createElement('div');
			
			no_res_div.className = 'as_no_res';
			
			appendText(no_res_div, 'No associates found for \\'' + info + '\\'. He/she may already have been added.');
			with_auto.appendChild(no_res_div);
		}
		
		//console.log(search);
		return search;
	});
}