I know how the extends pointer in PHP OOP works, but how does the implements one work…
class one
{
var $one;
}
class two implements one
{
var $two;
}
how does this work?
I know how the extends pointer in PHP OOP works, but how does the implements one work…
class one
{
var $one;
}
class two implements one
{
var $two;
}
how does this work?
I know how the extends pointer in PHP OOP works
What does that mean?
deleted
Implements is for interfaces. An interface is where you define the skeleton structure of a class and then you implement the skeleton with another class that puts some meat on the bones!
For example, imagine we are creating a library that will allow a user to connect to a number of different databases using a standard API. What we will create is a number of different classes with this API. This is where an interface is used.
<?php
interface iDatabaseConnection {
public function connect ( $host, $username, $password );
} // End interface
?>
Now any class that implements this interface has to provide a connect method that takes the three parameters $host, $username and $password or PHP will throw an error.
<?php
class MySQLConnection implements iDatabaseConnection {
public function connect ( $host, $username, $password ) {
// Connect here
} // End method
} // End class
?>
This way you can be sure that every class that implements iDatabaseConnection will stick to the exact same API structure
Sean
So basically its a template
Yes, but don’t call it that
Sean