Parse error: syntax error, unexpected T_VARIABLE in /home/public_html/search7.php on line 22
<html>
<head>
<title>designplace.org search script</title>
<meta name="author" content="Steve R, http://www.designplace.org/">
</head>
<body>
<form name="form" action="search.php" method="get">
<input type="text" name="q" />
<input type="submit" name="Submit" value="Search" />
</form>
<?php
// Get the search variable from URL
$var = @$_GET['q'] ;
$trimmed = trim($var) //trim whitespace from the stored variable
// rows to return
$limit=10;
// check for an empty string and display a message.
if ($trimmed == "") ;
{
echo "<p>Please enter a search...</p>";
exit;
}
// check for a search parameter
if (!isset($var))
{
echo "<p>We dont seem to have a search parameter!</p>";
exit;
}
//connect to your database ** EDIT REQUIRED HERE **
mysql_connect("localhost","david","dave"); //(host, username, password)
//specify database ** EDIT REQUIRED HERE **
mysql_select_db("customers") or die("Unable to select database"); //select which database we're using
// Build SQL Query
$query = "select * from the_table where 1st_field like \\"%$trimmed%\\"
order by 1st_field"; // EDIT HERE and specify your table and field names for the SQL query
$numresults=mysql_query($query);
$numrows=mysql_num_rows($numresults);
// If we have no results, offer a google search as an alternative
if ($numrows == 0)
{
echo "<h4>Results</h4>";
echo "<p>Sorry, your search: "" . $trimmed . "" returned zero results</p>";
// google
echo "<p><a href=\\"http://www.google.com/search?q="
. $trimmed . "\\" target=\\"_blank\\" title=\\"Look up
" . $trimmed . " on Google\\">Click here</a> to try the
search on google</p>";
}
// next determine if s has been passed to script, if not use 0
if (empty($s)) {
$s=0;
}
// get results
$query .= " limit $s,$limit";
$result = mysql_query($query) or die("Couldn't execute query");
// display what the person searched for
echo "<p>You searched for: "" . $var . ""</p>";
// begin to show results set
echo "Results";
$count = 1 + $s ;
// now you can display the results returned
while ($row= mysql_fetch_array($result)) {
$title = $row["1st_field"];
echo "$count.) $title" ;
$count++ ;
}
$currPage = (($s/$limit) + 1);
//break before paging
echo "<br />";
// next we need to do the links to other results
if ($s>=1) { // bypass PREV link if s is 0
$prevs=($s-$limit);
print " <a href=\\"$PHP_SELF?s=$prevs&q=$var\\"><<
Prev 10</a>  ";
}
// calculate number of pages needing links
$pages=intval($numrows/$limit);
// $pages now contains int of pages needed unless there is a remainder from division
if ($numrows%$limit) {
// has remainder so add one page
$pages++;
}
// check to see if last page
if (!((($s+$limit)/$limit)==$pages) && $pages!=1) {
// not last page so give NEXT link
$news=$s+$limit;
echo " <a href=\\"$PHP_SELF?s=$news&q=$var\\">Next 10 >></a>";
}
$a = $s + ($limit) ;
if ($a > $numrows) { $a = $numrows ; }
$b = $s + 1 ;
echo "<p>Showing results $b to $a of $numrows</p>";
?>
</body>
</html>
// Build SQL Query
$query = "select * from the_table where 1st_field like \\"%$trimmed%\\"
order by 1st_field"; // EDIT HERE and specify your table and field names for the SQL query
ok the table is called user_info and the first column/field is user_id so i have
// Build SQL Query
$query = "select * from user_info where user_id like \\"%$trimmed%\\"
order by user_id"; // EDIT HERE and specify your table and field names for the SQL query
the rest of the fields/columns are user_first_name user_surname user_email user_mobile etc etc
do i need to add all the fields/columns to this line, if so would it be
// Build SQL Query
$query = "select * from user_info where user_id like \\"%$trimmed%\\, user_first_name like \\"%$trimmed%\\, user_surname like \\"%$trimmed%\\, user_email like \\"%$trimmed%\\, user_mobile like \\"%$trimmed%\\"
order by user_id"; // EDIT HERE and specify your table and field names for the SQL query
// Build SQL Query
$query = "
select
user_first_name
, user_surname
, user_email
, user_mobile
from
user_info
where
user_id
like
'%" . $trimmed ."%'
order by
user_id"; // EDIT HERE and specify your table and field names for the SQL query
$numresults=mysql_query($query) or die(mysql_error());