Can't find error

Python, Perl and Golang Python
1

Here is my problem:

And here is my solution:

And this is the error that I am getting:
pythp

@cpradio

1 Like
2

You missed this instruction

if v is ommited, fill the array with undefined

You can fix that by changing your definition to

def prefill(n,v = 'undefined'):

However, this will only get you to the next error

489×686 28.1 KB

Be sure to read the instructions again for that one too

if n is anything other than an integer or integer-formatted string (e.g. ‘123’) that is >=0, throw a TypeError

When throwing a TypeError, the message should be n is invalid, where you replace n for the actual value passed to the function.

The test is providing -5, which is less than 0, so your logic should be throwing a TypeError with the message of “n is invalid”

3

here is my updated code:

But I am getting a new error:

4

Okay, so you are getting closer

First thing, you have two of the following conditions

    if type(n) == str:
        n = int(n)

You need to keep the first one, and it needs to be further towards the top, which gives you (as you can’t compare n to 0 or n < 0 without it being cast to an int first)

    if type(n) == str:
        n = int(n)
    if n == 0:
        return []
    if n<0:
        return n + "is invalid"

Now you need to actually test for an invalid int, using a try/except, because if they pass in ‘j’, it will fail due to a ValueError being returned.

    if type(n) == str:
        try:
            n = int(n)
        except ValueError:
            raise TypeError(n + ' is invalid')
    if n == 0:
        return []
    if n<0:
        return n + "is invalid"

Note, how I raise a TypeError, we need to do that for when n < 0 too

    if type(n) == str:
        try:
            n = int(n)
        except ValueError:
            raise TypeError(n + ' is invalid')
    if n == 0:
        return []
    if n<0:
        raise TypeError(str(n) + ' is invalid')

Lastly, if you just do those, you will get another failing test due to n == None, to resolve that

    if n == None:
        raise TypeError('None is invalid')
    if type(n) == str:
        try:
            n = int(n)
        except ValueError:
            raise TypeError(n + ' is invalid')
    if n == 0:
        return []
    if n<0:
        raise TypeError(str(n) + ' is invalid')

Finally, the entire script now looks like:

def prefill(n,v = 'undefined'):
    a = []
    if n == None:
        raise TypeError('None is invalid')
    if type(n) == str:
        try:
            n = int(n)
        except ValueError:
            raise TypeError(n + ' is invalid')
    if n == 0:
        return []
    if n<0:
        raise TypeError(str(n) + ' is invalid')
        
        
    while len(a)<=n:
        a.append(v)
    del a[-1]
    return a
5

That is clever !

6

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