Array Patterns

PHP
1

Hello,

If you an array that can have 1-24 numbers in it, could be different lenghts.

$set = array(5,6,7,8,15,16,17);

I want to find out how many different sets of number are in the array. like in this array ther are 2 sets of congruent numbers: 5,6,7,8 and 15,16,17.

How can php tell me how many different sets are in an array and what is first and last value of each set is? I looked into preg_match and this whitch does not work:

	$set = array(5,6,7,8,15,16,17);
	$len = count($set);

	foreach ($set as $key => $value) {
		$new = $value;
		//$new++;
		
		if($value == $new++){
			echo "yes";
		} else {
			echo "no";
		}	
		
		echo "New: ". $new . " Value ". $value;		
	}

Thank you,

Boot Straps

2

Could you make a clear example? Maybe I can help.

3

oh yes,

I have table of week days and hours. Using Javascript I have an array of the selected hours of a day that are selected. I send the array to php by hidden form field. The array may look like:

$set = array(5,6,7,8,15,16,17);

So in my first post there are 2 sets of congruent sets of numbers: 5,6,7,8 and 15,16,17 each representing in hours on a 24 hours block time. 1st set starts at hour 5 and ends 4 hours later, using 4 how many congruent numbers in a row and so forth for the 2nd set 15,16,17.

$set = array(5,6,7,8,15,16,17);
	$len = count($set);
	$kio = array();
	foreach ($set as $key => $value) {
		$new = $key;		
		$tuo = $value - $key;
		$kio[] = $tuo;	
	}	

	foreach ($kio as $key2 => $value2) {
		echo $key2 . " " . $value2 . "<br>";
	}
	
	$result = array_unique($kio);
	print_r($result);


	$len2 = count($result);
	echo  " len2: " . $len2;
	
	echo "<br><br>there are $len2 Sets: <br>";
	$i = 0;
	$cua = array_count_values($kio);
	foreach ($result as $key3 => $value3) {
		//echo "<br>" .  $key3 . " " . $value3;
		
		foreach ($cua as $key4 => $value4) {
			$value4++;
			echo "Set $i starts with $value4 and is $value4 Long <br>";
		}		
		$i++;
	}

Between my first post and now I was able make this. Does not work but very close I think.

4

So the term set you mean that consists of continue number?

5

Yes like 123456 but not 1234568.

6

Hope this help.


		$set = array(5,6,7,8,15,16,17); 
    $len = count($set); 
    $kio = array();
	
	$previous_number = 0;
	$total_set = 0;
    foreach ($set as $key => $value) { 
        if(($value-$previous_number) != 1 && $key!=0) {
			$total_set++;
		}
		elseif($key==0) $total_set++;
		$kio[$total_set][] = $value;
		$previous_number = $value;
    }     

    print_r($kio); 


    $len2 = count($kio); 
    echo  " len2: " . $len2; 
     
    echo "<br><br>there are $len2 Sets: <br>"; 
    for($i=1;$i<=$total_set;$i++)
	{
		echo "Set $i starts with ".$kio[$i][0]." and is ".count($kio[$i])." Long <br>";
	}
7

thietkeweb,
You are great. :smiley: It works prefect. Now I put it in a function and tomorrow i’ll try to get ajax to run the php function.

Thank you thank you.

Boot Straps

8

You’re welcome. :slight_smile: