Use Status Button in a Table raw

PHP
1

Hi, I am new in Php. Please Help me to short out this problem
I am trying to use a status button in a table raw when click the status button then only update the status field in database. and when click the status button all raw is submitted.
I am writing this code below

guest.php

<!DOCTYPE html>
<?php
include 'connect.php';
?>
</br></br>
<h4><b>Guest Status </b></h4>
<div class="row">
	<div class="panel-body" style="height: auto;">
		<form class="form-horizontal" role="form" action="guestExe.php" method="POST">
			<div class="form-group">								
				<div class="panel-body" style="height: auto;  padding:5px;">
					<div class="col-md-12" >											   
						<label for="name" class="col-md-3 control-label">Name:</label>
						<div class="col-md-3">
							<input type="text" class="form-control" id="name" name="name"  >
						</div>
						<label for="mobileNo" class="col-md-3 control-label">Mobile No:</label>
						<div class="col-md-3">
							<input type="text" class="form-control" id="mobileNo" name="mobileNo">
						</div> 						
					</div>
				</div>
				<div class="panel-body" style="height: auto;  padding:5px;">
					<div class="col-md-12">											   
						<label for="email" class="col-md-3 control-label">E mail:</label>
						<div class="col-md-3">
							<input type="text" class="form-control" id="email" name="email"  >
						</div> 
					</div>
				</div>			
			</div>
			<div class="panel-body" style="height: auto;">
				<div class="col-sm-12">
					<button type="submit" name="submit" class="btn btn-warning" > SUBMIT</button>
				</div>
			</div>						
		</form>
	</div>
</div>
<table class="table table-bordered" style="width:100%; border:2px solid red;">
	<thead >
		<tr  style="background-color:red;">
			<th>SL/NO</th>
			<th>Name</th>
			<th>MobileNo</th>
			<th>E-mail</th>
			<th>Status</th>
			<!--<th>Edit</th>
			<th>Delete</th> -->
		</tr>
	</thead>
	<tr>
	<?php   
	$result = mysqli_query($con,"SELECT * FROM guest");
	while($row = mysqli_fetch_array($result ))
	{ 		
	echo '<tr>
			<td>'.$row['Id'].'</td>
			<td>'.$row['name'].'</td>
			<td>'.$row['mobileNo'].'</td>
			<td>'.$row['email'].'</td>' ?>
			
			<td><button class="btn waves-effect waves-light right" type="submit" name="status"	value="OK"> APPROVE </button></td>			
		</tr><?php 		
	}			
?>		
</tbody>
</table>

guestExe.php

<!DOCTYPE html>
<head> <title>ABC</title></head>
<body>
<?php
//error_reporting('1');
include 'connect.php';
if(isset($_POST['submit']))
	{
		$name =  $_POST['name'];
		$mobileNo = $_POST['mobileNo'];
		$email = $_POST['email'];
		$sql = "INSERT INTO 
		guest(name,mobileNo,email) VALUES ('$name','$mobileNo','$email')";
		if(!mysqli_query($con, $sql))
		{
		die('conection failed'.mysqli_error($con));
		}
		else
		{
			 echo "SUccsesively Enter";
		}
	}
 header('Location: guest.php');
?> 

</body>
</html>
2

The code you have with the status button is outside of the form, so you will need to enclose that section in another set of <form> tags. You’ll need to provide the guest id as part of the form data, so your code knows which guest to change the status for. You’ll also need to modify the loop to display the current status in order for the screen display to make sense to the user.

Does the status only have two possible values, so you are just switching from one to the other?

3

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