Skipping array element in foreach loop

PHP
1

In this sample code, is it possible to skip an element in the array, say, 3? If so, how?

<?php
$arr = array(1, 2, 3, 4);
foreach ($arr as &$value)
{
$value = $value * 2;
}

Thanks :slight_smile:

2 
<?php

$arr = array(1, 2, 3, 4);

foreach ($arr as &$value) {
    switch($value) {
        
        case 3:
            echo '<p>Skipped the number 3</p>';
            break 1;
        default:
            $value = $value * 2;
            echo "<p>The calulcated value is: $value</p>";
            break;
}
}
?>

From the PHP manual:

break ends execution of the current for, foreach, while, do-while or switch structure.
break accepts an optional numeric argument which tells it how many nested enclosing structures are to be broken out of.

3 

foreach ( $array as $value ) {
  if ( $value == 3 )
    continue; # Skips

  # Code goes here...
}
4

Some SPL fun, for giggles. :smiley:


<?php
class ValueFilter extends FilterIterator
{
  protected
    $value;

  public function __construct($value, $iterator){
    $this->value = $value;
    parent::__construct($iterator);
  }

  public function accept(){
    return $this->value !== $this->current();
  }
}

$array = array(1, 2, 3, 4, 5, 6);

foreach(new ValueFilter(3, new ArrayIterator($array)) as $value){
  echo $value, PHP_EOL;
}

/*
  1
  2
  4
  5
  6
*/