PHP MySQLI code not working
$q = “UPDATE users SET password = ‘6c55803d6f1d7a177a0db3eb4b343b0d50f9c111’ WHERE id = ‘1’;”;
Dot knows but some cause it keeps giving me the following error:
Expects parameter 1 to be mysqli, null given[/B]
Can anyone help me
Thanks in advance
Where are you defining/declaring the variable $dbc?
As shown in the PHP Manual, $dbc needs to be the result of mysqli_connect (second example)
Also, in your SQL, you do not need the second-to-last semicolon.
$q = "UPDATE users SET password = '6c55803d6f1d7a177a0db3eb4b343b0d50f9c111' WHERE id = '1';";
$q = "UPDATE users SET password = '6c55803d6f1d7a177a0db3eb4b343b0d50f9c111' WHERE id = 1";
Also note that you don’t need to (and probably shouldn’t) quote integer values in your SQL.