claro
January 23, 2012, 7:15pm
1
This thing run in FF but not in Opera. It displays the ff.
Warning: mktime() expects parameter 4 to be long, string given in C:\xampp
$Date = str_replace("/","-",$Date);
$Month = substr($Date,0, 2)."<br/>";
$Day = substr($Date, strpos($Date, '-') + 1, 2)."<br/>";
$Year = substr($Date, strpos($Date, '-') + 4);
echo(date("m-d-Y",mktime(0,0,0,$Month,$Day,$Year))."<br />");
Is it the browser or my codes? thanks.
Hello,
a couple of changes in your code:
$Date = '10/10/2011';
$Date = str_replace("/","-",$Date);
$Month = substr($Date,0, 2)."<br/>";
$Day = substr($Date, strpos($Date, '-') + 1, 2)."<br/>";
$Year = substr($Date, strpos($Date, '-') + 4);
echo date("m-d-Y", mktime(0,0,0,(int) $Month,(int) $Day,(int) $Year));
Anyway, PHP is processed on server side, so the result should be exactly the same throughout all browsers.
Cups
January 23, 2012, 8:45pm
3
$Date = "10/10/2011";
echo(date("m-d-Y",strtotime($Year))."<br />");
That one liner should work, though test very carefully 9/10/2011 and 10/9/2011 to check which you mean to be the 9th October, and importantly which PHP understands to be the 9th October – make sure they match or you may find yourself having to [fphp]explode/fphp the incoming $Date first.
claro
January 24, 2012, 6:11am
4
The error is gone and it works now but the format I’m looking is not the same as the result. I’m planning to save it in my db, so I should follow the Y-m-d format which mysql understand, but when I tried the code it appears to be 1970-01-01. what’s the problem in it?
I followed this code
$Date = str_replace("/","-",$Date);
$Month = substr($Date,0, 2)."<br/>";
$Day = substr($Date, strpos($Date, '-') + 1, 2)."<br/>";
$Year = substr($Date, strpos($Date, '-') + 4);
echo(date("Y-m-d",mktime(0,0,0,(int)$Year,(int)$Month,(int)$Day))."<br />");
claro
January 24, 2012, 8:56am
5
Ok, this end my agony. I just change its format and viola.
THank you.
$Date = str_replace(“/”,“-”,$Date);
$Month = substr($Date,0, 2).“<br/>”;
$Day = substr($Date, strpos($Date, ‘-’) + 1, 2).“<br/>”;
$Year = substr($Date, strpos($Date, ‘-’) + 4);
$Date = date(“Y-m-d”,mktime(0,0,0,$Month,$Day,$Year)).“<br />”;
echo $Date;
Cups
January 24, 2012, 9:04am
6
Cups:
$Date = "10/10/2011";
echo(date("m-d-Y",strtotime($Year))."<br />");
That one liner should work, though test very carefully 9/10/2011 and 10/9/2011 to check which you mean to be the 9th October, and importantly which PHP understands to be the 9th October – make sure they match or you may find yourself having to [fphp]explode/fphp the incoming $Date first.
Sorry, SB
$Date = "10/10/2011";
echo date("Y-m-d",strtotime($Date)) ;