json_decode/encode true/false

PHP
1

Does this ( http://php.net/manual/en/migration56.incompatible.php#migration56.incompatible.json-decode ) mean that there is no longer possible to use json_encode(false) ?

2

You missed this?

Migrating from PHP 5.5.x to PHP 5.6.x

.

json_decode() strictness ¶

json_decode() now rejects non-lowercase variants of the JSON literals true, false and null at all times, as per the JSON specification, and sets json_last_error() accordingly. Previously, inputs to json_decode() that consisted solely of one of these values in upper or mixed case were accepted.

This change will only affect cases where invalid JSON was being passed to json_decode(): valid JSON input is unaffected and will continue to be parsed normally.

3

Actually I did read that before the link I gave above! but I still have difficulty to understand what exactly it means! please clarify with example.

4

Sorry, I’m confused.

An example of how different PHP versions deal with json_decode and how it might affect json_encode ?

What part are you having trouble with?

5

please just explain what that statement on manual mean with example!

6

Just that

There is NO example to your question as you’ve asked it.

7

Can’t you just explain/clarify what that statement mean?

8

Sorry, but it seems you are asking for me to do your thinking.
I have enough trouble doing my own.

9

You are asking the wrong question.

Let’s say you have the following json

{
  my_value: FALSE
}

json_decode will now fail, because FALSE isn’t all lowercase. If its value was FaLsE, it would fails as well. It will only succeed if the value is false

1 Like
10

Thanks for explanation.

11

To be more precise - PHP now correctly recognizes that the above is NOT JSON, as it does not comply with the JSON specification.

2 Likes
12

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