How to submit a form / click button?

JavaScript
1

How to add to this working bookmarklet

javascript:void(window.open(%27https://developers.facebook.com/tools/debug/sharing/?q=%27+window.location.href,%27_blank%27));

submitting of the following form?

<form rel="async" action="/tools/debug/sharing_rescrape/?elem_id=u_0_0" method="post" onsubmit="return window.Event &amp;&amp; Event.__inlineSubmit &amp;&amp; Event.__inlineSubmit(this,event)" id="u_0_6">
     <input type="hidden" name="fb_dtsg" value="AQH1ok_IYCTG:AQGqk6oXVqIV" autocomplete="off">
     <input type="hidden" autocomplete="off" name="url" value="http://example.com/new-page.html/">
     This URL hasn't been shared on Facebook before.
     <button value="1" class="_42ft _4jy0 _3-9a _4jy3 _517h _51sy" type="submit">
          Fetch new information
     </button>
     <span class="img _55ym _55yn _55yo _5tqs" aria-busy="true" role="progressbar" aria-valuemin="0" aria-valuemax="100" aria-valuetext="Loading..."></span>
</form>

Tried to get it done with adding of document.form[0].submit(); and document.getElementsByTagName('button').submit(); but failed. Any help is highly appreciated:)

2

Your code would have been much more readable if you had formatted and indented it properly. I took the liberty to do it this time, because it was very hard to understand the way it was before.

2 Likes
3 
onsubmit="return window.Event &amp;&amp; Event.__inlineSubmit &amp;&amp; Event.__inlineSubmit(this,event)"

I’m… not entirely sure what this code is meant to do… but anyway, before the word return, stick your window.open command in.

4

@m_hutley firstly about the purpose: on the url https://developers.facebook.com/tools/debug/sharing/ is a code debugger. The debugger looks different depending on was an url already ever checked or not. But the submit button of debugger is always the same - this is the form and button i cited in the first post.

What i want to achieve:

  1. Step 1 (already done): to transfer an url of current (any) page into new tab, add it to the debugger url. This part works already with the code part javascript:void(window.open(%27https://developers.facebook.com/tools/debug/sharing/?q=%27+window.location.href,%27_blank%27));
  2. Step 2 (need help): i want start the debugger through submitting the button in the form.

Your code doesn’t work for me :frowning:

I used it as javascript:void(window.open('https://developers.facebook.com/tools/debug/sharing/?q='+window.location.href,'_blank'));onsubmit='return window.Event &amp;&amp; Event.__inlineSubmit &amp;&amp; Event.__inlineSubmit(this,event)'

After click on it the content of the current page was replaced with the text return window.Event && Event.__inlineSubmit && Event.__inlineSubmit(this,event), like on screenshot - the page with debugger was remaining as it was, without to start the debugger.

5

This topic was automatically closed 91 days after the last reply. New replies are no longer allowed.