I have achieved the result by running separate reduce functions for sum and count and then creating finalobj using Object.entries. Can this be achieved with less and better code: { A1: { Avg: 4, Count: 1, Sum: 4 }, A13: { Avg: 3, Count: 1, Sum: 3 }, A4: { Avg: 1, Count: 1, Sum: 1 }, C6: { Avg: 1, Count: 1, Sum: 1 }, M1: { Avg: 1.75, Count: 4, Sum: 7 } }
My Code:
const riskTypeNoWithSelectedValue = [
{
"riskTypeNo": "A1",
"selectedValue": 4
},
{
"riskTypeNo": "M1",
"selectedValue": 4
},
{
"riskTypeNo": "C6",
"selectedValue": 1
},
{
"riskTypeNo": "M1",
"selectedValue": 1
},
{
"riskTypeNo": "M1",
"selectedValue": 1
},
{
"riskTypeNo": "A4",
"selectedValue": 1
},
{
"riskTypeNo": "M1",
"selectedValue": 1
},
{
"riskTypeNo": "A13",
"selectedValue": 3
}
];
const sumrRiskTypeNo = riskTypeNoWithSelectedValue.reduce((accumulator, {riskTypeNo, selectedValue}) => (accumulator[riskTypeNo] = (accumulator[riskTypeNo] || 0) + selectedValue, accumulator), {});
const countRiskTypeNo = riskTypeNoWithSelectedValue.reduce((accumulator, {riskTypeNo, selectedValue}) => (accumulator[riskTypeNo] = (accumulator[riskTypeNo] || 0) + 1, accumulator), {});
const finalObj = {};
Object.entries(sumrRiskTypeNo).forEach(([k, v]) => {
finalObj[k] = {"Sum": v, "Count": countRiskTypeNo[k], "Avg": v/countRiskTypeNo[k]};
});
console.log(finalObj);