How Sumarize leave time proportionally and correctly - mysql

In mysql database i created “leave” table:

CREATE TABLE `leave` ( 
`ID_LEAVE` int(11) NOT NULL,
`ID_WORKER` int(11) NOT NULL,
`BEGIN_DATE` datetime DEFAULT NULL,
`END_DATE` datetime DEFAULT NULL
)

INSERT INTO `leave` 
(`ID_LEAVE`, `ID_WORKER`, `BEGIN_DATE`, `END_DATE`) VALUES
(3, 26, '2019-03-20 07:00:00', '2019-03-21 15:00:00'),
(4, 22, '2019-03-20 07:00:00', '2019-03-20 15:00:00');

“Workers” table:

CREATE TABLE `workers` (
`ID_WORKER` int(11) NOT NULL,
`FNAME` varchar(20) NOT NULL,
`LNAME` varchar(20) NOT NULL
)

INSERT INTO `workers` (`ID_WORKER`, `FNAME`, `LNAME`) VALUES
(22, 'ALAN', 'FAST'),
(23, 'LEON', 'SPEED'),
(24, 'ADAM', 'GREEN'),
(25, 'DAVID', 'BUCS'),
(26, 'JACK', 'FAR'),
(27, 'ADAM', 'GAX'),
(28, 'ANDREW', 'WORM');

“Orders” table:

CREATE TABLE `orders` (
`ID_ORDER` int(11) NOT NULL,
`DESC_ORDER` varchar(50) NOT NULL,
`NUMBER_ORDER` varchar(30) NOT NULL
)

INSERT INTO `orders` (`ID_ORDER`, `DESC_ORDER`, `NUMBER_ORDER`) VALUES
(19, 'TEST', 'TEST'),
(20, 'TEST2', 'TEST2'),
(21, 'TEST3', 'TEST3'),
(22, 'TEST4', 'TEST4');

“Order_status” table (I’m sorry for that’s not in order):

CREATE TABLE `order_status` (
`ID_STATUS` int(11) NOT NULL,
`ID_ORDER` int(11) NOT NULL,
`ID_WORKER` int(11) NOT NULL,
`BEGIN_DATE` datetime NOT NULL,
`END_DATE` datetime NOT NULL,
`ORDER_DONE` tinyint(1) DEFAULT NULL
) 

INSERT INTO `order_status` (`ID_STATUS`, `ID_ORDER`, `ID_WORKER`, `BEGIN_DATE`, `END_DATE`, `ORDER_DONE`) VALUES
(30, 19, 26, '2019-03-18 06:40:21', '2019-03-18 15:22:32', 'NO'),
(31, 19, 25, '2019-03-18 06:51:23', '2019-03-18 15:11:10', 'NO'),
(32, 19, 26, '2019-03-20 06:23:32', '2019-03-20 15:33:11', 'NO'),
(33, 19, 25, '2019-03-20 06:44:42', '2019-03-20 15:16:22', 'NO'),
(34, 19, 26, '2019-03-22 06:44:32', '2019-03-22 11:44:54', 'YES'),
(35, 19, 25, '2019-03-22 06:59:22', '2019-03-22 12:33:33', 'YES'),
(42, 20, 22, '2019-03-18 06:44:23', '2019-03-18 15:11:23', 'NO'),
(43, 20, 23, '2019-03-18 06:50:45', '2019-03-18 15:15:44', 'NO'),
(44, 20, 22, '2019-03-19 06:40:20', '2019-03-19 15:23:30', 'NO'),
(45, 20, 22, '2019-03-21 06:55:45', '2019-03-21 16:03:23', 'NO'),
(46, 20, 22, '2019-03-22 06:55:45', '2019-03-22 13:23:44', 'YES'),
(47, 20, 23, '2019-03-19 06:45:23', '2019-03-19 15:33:23', 'NO'),
(48, 20, 23, '2019-03-20 06:45:23', '2019-03-20 15:22:23', 'NO'),
(49, 20, 23, '2019-03-21 06:50:33', '2019-03-21 15:33:11', 'NO'),
(50, 20, 23, '2019-03-22 06:44:23', '2019-03-22 12:22:44', 'YES'),
(51, 21, 24, '2019-03-18 06:46:55', '2019-03-18 15:23:22', 'NO'),
(52, 21, 24, '2019-03-19 06:55:33', '2019-03-19 15:23:33', 'NO'),
(53, 21, 24, '2019-03-20 06:50:59', '2019-03-20 15:44:02', 'NO'),
(54, 21, 24, '2019-03-21 06:44:33', '2019-03-21 15:23:33', 'YES'),
(55, 21, 24, '2019-03-22 06:49:33', '2019-03-22 11:22:32', 'YES'),
(56, 22, 27, '2019-03-18 06:50:12', '2019-03-18 15:22:15', 'NO'),
(57, 22, 28, '2019-03-18 06:44:12', '2019-03-18 15:33:44', 'NO'),
(58, 22, 27, '2019-03-19 06:53:22', '2019-03-19 15:22:33', 'NO'),
(59, 22, 28, '2019-03-19 06:33:22', '2019-03-19 15:15:22', 'NO'),
(60, 22, 28, '2019-03-21 06:33:22', '2019-03-21 15:01:56', 'NO'),
(61, 22, 27, '2019-03-22 06:33:22', '2019-03-22 11:05:33', 'YES'),
(62, 22, 27, '2019-03-21 06:45:22', '2019-03-21 15:33:33', 'NO'),
(63, 22, 28, '2019-03-22 06:51:33', '2019-03-22 10:35:55', 'YES'),
(64, 19, 25, '2019-03-19 06:50:32', '2019-03-19 15:33:44', 'NO'),
(65, 19, 26, '2019-03-19 06:44:50', '2019-03-19 15:22:33', 'NO'),
(66, 19, 25, '2019-03-21 06:50:50', '2019-03-21 15:33:33', 'NO');
(67, 22, 27, '2019-03-20 06:51:32', '2019-03-20 15:20:33', 'NO');

What i’ve done:

I can to sumarize “Order time” of each other workers. I have selected workers (LNAME, FNAME) orders (DESC_ORDER and NUMBER_ORDER) and “TOTAL TIME” on order from each other workers correctly too. I wrote the mysql command in below:

SELECT workers.FNAME, 
workers.LNAME, 
order_statusAgg.NUMBER_ORDER,
order_statusAgg.DESC_ORDER, 
SEC_TO_TIME(SUM(order_statusAgg.stime)) AS 'ORDER TIME'
FROM workers
LEFT JOIN (
SELECT order_status.ID_WORKER, orders.NUMBER_ORDER, orders.DESC_ORDER, 
SUM((TIME_TO_SEC(order_status.END_DATE) - TIME_TO_SEC(order_status.BEGIN_DATE))) AS stime 
FROM order_status INNER JOIN orders
ON orders.ID_ORDER = order_status.ID_ORDER
GROUP BY order_status.ID_WORKER) order_statusAgg
ON workers.ID_WORKER = order_statusAgg.ID_WORKER
WHERE order_statusAgg.NUMBER_ORDER LIKE 'TEST'
GROUP BY workers.ID_WORKER;

Then i get:

|  FNAME  | LNAME   |  NUMBER_ORDER | DESC_ORDER | ORDER TIME | LEAVE_TIME | TOTAL_TIME |
+---------+---------+---------------+------------+------------+------------+------------+
|  DAVID  |  BUCS   | TEST          | TEST       | 39:51:33   | 00:00:00   | 39:51:33   |
+---------+---------+---------------+------------+------------+------------+------------+
|  JACK   |  FAR    | TEST          | TEST       | 31:29:55   | 16:00:00   | 47:29:55   |
+---------+---------+---------------+------------+------------+------------+------------+```

I’ve analyzed 2 days (20.03.2019 and 21.03.2019). Photos are in below:!
(https://i.stack.imgur.com/ooDoz.jpg)

Now i need mysql query that sumarize leave time correctly and PROPORTIONALLY to pattern described in below:

for example for leave time where ID_WORKER = 26 (he has order “TEST”)

                '08:31:40'                                      '08:31:40'

(-------------------------------------------------) * 8:00:00 = (--------------) * 8:00:00 = 2:00:16
‘08:31:40’ + ‘08:37:00’ + ‘08:53:03’ + ‘08:29:01’ ‘34:30:44’
What I’ve tried: I’ve tried sum leave time by mysql query in below:

SELECT workers.FNAME, 
workers.LNAME, 
order_statusAgg.NUMBER_ORDER,
order_statusAgg.DESC_ORDER, 
SEC_TO_TIME(SUM(order_statusAgg.stime)) AS 'ORDER TIME', 
IFNULL(SEC_TO_TIME(SUM(leaveAgg.ltime)),'00:00:00') AS 'LEAVE TIME'
FROM workers
LEFT JOIN (SELECT leave.ID_WORKER, SUM((datediff(leave.BEGIN_DATE, leave.END_DATE) + 1) * (time_to_sec(time(leave.END_DATE)) - time_to_sec(time(leave.BEGIN_DATE)))) AS ltime FROM leave
LEFT JOIN
(SELECT ID_WORKER, MIN(BEGIN_DATE) AS 'MIN_BEGIN_DATE', MAX(END_DATE) AS 'MAX_END_DATE' 
FROM order_status GROUP BY ID_WORKER) ordstat ON 
leave.ID_WORKER = ordstat.ID_WORKER 
WHERE leave.END_DATE <= MAX_END_DATE AND leave.BEGIN_DATE >= MIN_BEGIN_DATE GROUP BY leave.ID_WORKER) leaveAgg
ON leaveAgg.ID_WORKER = workers.ID_WORKER
LEFT JOIN (
SELECT order_status.ID_WORKER, orders.NUMBER_ORDER, orders.DESC_ORDER, 
SUM((TIME_TO_SEC(order_status.END_DATE) - TIME_TO_SEC(order_status.BEGIN_DATE))) AS stime 
FROM order_status INNER JOIN orders
ON orders.ID_ORDER = order_status.ID_ORDER
GROUP BY order_status.ID_WORKER) order_statusAgg
ON workers.ID_WORKER = order_statusAgg.ID_WORKER
WHERE order_statusAgg.NUMBER_ORDER LIKE 'TEST'
GROUP BY workers.ID_WORKER;

But I’m afraid that isn’t enough because it only adds for example:

31:29:55 + 16:00:00 = 47:29:55

I wanna get that result:

31:29:55 + 2:00:16 = 34:30:11

CAUTION! If someone get’s 2 or more days of leaves i cannot do that like this:

                '08:31:40'                                      

(-------------------------------------------------) * 16:00:00
‘08:31:40’ + ‘08:37:00’ + ‘08:53:03’ + ‘08:29:01’
I have to analyze every day like that example where i explained.

I know that’s more difficult question i cannot find any clue how to solve it. Can someone please what should i change or add. Thank you in advance for any help or advice.

That is not to your question, excuse me about… But why don’t you use auto increment in your primary keys? Actually this gonna be a really big problem in your project.

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