How could I change the printf's %s function to PHP variables?

PHP
1

The title may be strange, but I think this is a legitimate problem. It’s mostly PHP but it does have a little database stuff in it. I want to know how to change the %s to actual PHP variables.

Here’s what I’m focused on:

    printf('

  </div><div class="flol">
        <h1>%s</h1>
        <br>
        <h2>By %s</h2>
        <br>
        <br>
        <h3>%s</h3>
  </div>

  <div class="flor">
    <div style="float:right; background-color:#333; padding:10px;">
    <img src="assets/placeholder.jpg" height="200" width="200">
    </div>
  </div>
    ', $row[0],$row[1], $row[2]);

How to I change the %s’s to $row[0], $row[1], etc.?

2

Simple. Don’t use printf. Use echo instead. Even better, use the output tags. And I mean for the variables. Don’t echo pure HTML.

Example

<?= $row['some_column'] ?>
1 Like
3

Have you tried running that code? It does exectly what you want it to :slight_smile:

4

Below alternatives will result to the same output.

$var1 = 'var1';
$var2 = 'var2';
$var3 = 'var3';

printf('</div><div class="flol">
        <h1>%s</h1>
        <br>
        <h2>By %s</h2>
        <br>
        <br>
        <h3>%s</h3>
  </div></div>', $var1, $var2, $var3);

or…

echo "</div><div class=\"flol\">
        <h1>$var1</h1>
        <br>
        <h2>By $var2</h2>
        <br>
        <br>
        <h3>$var3</h3>
  </div></div>";

or…

echo '</div><div class="flol">
<h1>'.$var1.'</h1>
<br>
<h2>By '.$var2.'</h2>
<br>
<br>
<h3>'.$var3.'</h3>
</div></div>';

or…

echo <<<EOT
</div><div class="flol">
<h1>$var1</h1>
<br>
<h2>By $var2</h2>
<br>
<br>
<h3>$var3</h3>
</div></div>
EOT;
5

Also, never just output something from the database to the screen. Always apply htmlspecialchars first to prevent Cross Site Scripting (XSS) attacks.

6

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