Having trouble here understanding preg_match

[9894770]

I have this code where I would like to convert a file (using ffmpeg) if the file does not have to correct extension. I’m using preg_match but I’m having problems.
When I manually convert the file it works and it works in php too but when I run this code along with ffmpeg it doesn’t work it doesn’t upload the file nor does it convert it.

<?php
// Access the $_FILES global variable for this specific file being uploaded // and create local PHP variables from the $_FILES array of information $fileName = $code_to_execute; // The file name $fileTmpLoc = $code_to_execute; // File in the PHP tmp folder $fileType = $code_to_execute; // The type of file it is $fileSize = $code_to_execute; // File size in bytes

if (preg_match("/.(wmv|avi|flv)$/i", $fileName) ) { shell_exec("ffmpeg -i uploads/".$code_to_execute." uploads/".$code_to_execute.""); // This condition is only if you wish to allow uploading of specific file types unlink($fileTmpLoc); // Remove the uploaded file from the PHP temp folder exit(); ?>

BUT
when I run this code it uploads the file but doesn’t convert it

<?php
// Access the $_FILES global variable for this specific file being uploaded // and create local PHP variables from the $_FILES array of information $fileName = $code_to_execute; // The file name $fileTmpLoc = $code_to_execute; // File in the PHP tmp folder $fileType = $code_to_execute; // The type of file it is $fileSize = $code_to_execute; // File size in bytes

if (!preg_match("/.(wmv|avi|flv)$/i", $fileName) ) { shell_exec("ffmpeg -i uploads/".$code_to_execute." uploads/".$code_to_execute.""); // This condition is only if you wish to allow uploading of specific file types unlink($fileTmpLoc); // Remove the uploaded file from the PHP temp folder exit(); ?>

There’s literally nothing different with the code except I added a "!" in front of preg_match turning it into !preg_match

What the hell is the difference and why doesn’t it work, someone help me out here T.T?

[lorenw]

The ! is a “not” preg_match so using ! you are saying that if it doesn’t match, do something.

[Lemon_Juice]

Also your regex should look like this:

preg_match("/\.(wmv|avi|flv)$/i", $fileName)

note the backslash before the dot. The dot means any character - if you don’t add the backslash then file names like videowmv, lavi, ect. will match the regex, too, while I suppose you only want video.vmw, l.avi, etc.

[9894770]

I want it to look for any file that doesn’t have the extensions .gif/png/mp4 and then I want ffmpeg to convert the file so if it’s a jpg it gets converted to png and if it’s an avi flv wmv it gets converted to mp4

[9894770]

I understand that but the conversion doesn’t work. So for example I’m saying if the extension doesn’t match .mp4 then convert but it doesn’t matter whether I use the “!” or not it still won’t convert…anyway around this?

Example (this won’t convert nor will it upload the file):

<?php if (!preg_match("/\.(mp4)$/i", $fileName)) { shell_exec("ffmpeg -i uploads/".$code_to_execute." uploads/".$code_to_execute.".mp4"); } ?>

[Mittineague]

Your code examples have $code_to_execute all over the place.

Obviously the code examples are not the real code being used. Can you post it?

[9894770]

<?php
// Access the $_FILES global variable for this specific file being uploaded
// and create local PHP variables from the $_FILES array of information
$fileName = $_FILES["uploaded_file"]["name"]; // The file name
$fileTmpLoc = $_FILES["uploaded_file"]["tmp_name"]; // File in the PHP tmp folder
$fileType = $_FILES["uploaded_file"]["type"]; // The type of file it is
$fileSize = $_FILES["uploaded_file"]["size"]; // File size in bytes
$fileErrorMsg = $_FILES["uploaded_file"]["error"]; // 0 for false... and 1 for true

else if (!preg_match("/\.(mp4)/i", $fileName) ) {
    shell_exec("ffmpeg -i uploads/".$_FILES["uploaded_file"]["type"]." uploads/".$_FILES["uploaded_file"]["type"].".mp4");
     // This condition is only if you wish to allow uploading of specific file types    
    unlink($fileTmpLoc); // Remove the uploaded file from the PHP temp folder
     exit();
} 
// Place it into your "uploads" folder mow using the move_uploaded_file() function
$moveResult = move_uploaded_file($fileTmpLoc, "uploads/$fileName");
// Check to make sure the move result is true before continuing
if ($moveResult != true) {
    echo "ERROR: File not uploaded. Try again.";
    exit();
} 
}
?>

[Mittineague]

Is safe_mode enabled?

http://php.net/manual/en/features.safe-mode.functions.php

shell_exec() (functional equivalent of backticks) This function is disabled when PHP is running in safe mode.

[9894770]

No it’s disabled…I didn’t necessarily have to use shell_exec() I could’ve just used exec() either one doesn’t work.

[Mittineague]

I know from limited past experience that exec() can be extremely picky

For example purposes only, lets say $_FILES["uploaded_file"]["type"] is “avi”
Substituting that into the command
shell_exec("ffmpeg -i uploads/".$_FILES["uploaded_file"]["type"]." uploads/".$_FILES["uploaded_file"]["type"].".mp4");
gives
shell_exec("ffmpeg -i uploads/avi uploads/avi.mp4");

That doesn’t look right to me.

[9894770]

I see what you’re saying so would something like this work?

<?php
exec("ffmpeg -i uploads/".$fileName.$fileType." uploads/".$fileName.".mp4");
?> 

Where $fileName = $_FILES["uploaded_file"]["name"];
and $fileType = $_FILES["uploaded_file"]["type"];

[9894770]

Ok so I got this working with this code

<?php
else if (preg_match("/\.(wmv)$/i", $fileType)) {
preg_replace("ffmpeg -i uploads/".$_FILES["uploaded_file"]["type"]." uploads/".$_FILES["uploaded_file"]["type"].".mp4"); 
unlink($fileTmpLoc); // Remove the uploaded file from the PHP temp folder
 exit();
}
?>

But now I need it to do another thing. Which is upload that converted file to the database…anyone help?