Format an array of number for display

PHP
1

Lets say I have an array full of years.


array(
    '1991',
    '1992',
    '1993',
    '1994',
    '1995',

    '1999',
    '2000',
    '2001'
)

How can I display that array as “1991-1995, 1999-2001”

Thanks guys :wink:

2

you mean “how do i find gaps in my array”?

Semi-sloppy way:


$curval = array[0];
foreach($array AS $year) {
  if($year != $curval + 1) {
     echo "-".$curval.", ".$year;
  }
  $curval = $year;
}
echo "-".$curval;

Note: Will look odd if the first value or last value in the array are a gap year (1995,2000,2001,2004 will be presented as: 1995-1995,2000-2001,2004-2004)

3

How about array_chunk?


$array = array( 
    '1991', 
    '1992', 
    '1993', 
    '1994', 
    '1995', 

    '1999', 
    '2000', 
    '2001' 
);
print_r(array_chunk($array, 5, true));
4

Would only work if the chunks are always the same size.

5

Yes, agreed!

6

There might be an easier way to do this, but this is how I got it done.


// Set needed variables
$years = array('1991', '1992', '1993', '1994', '1999', '2000', '2001', '2002');
$index = 0;
$delimitter = '';

foreach($years as $year) {
	
	// Get last index
	if($index != 0) {
		$last_index = $index - 1;	
	}
	// Get next index
	$next_index = $index + 1;
	
	if($index == 0) {
		echo $year->name;
			
	} elseif ($year->name - 1 == $years[$last_index]->name) {
		if($delimitter != '-') {
			$delimitter = '-';
			echo $delimitter;
		}
		if(isset($years[$next_index])) {
			if($years[$next_index]->name != $year->name + 1) {
				echo $year->name;
			}
		} else {
			echo $year->name;
		}
	} else {
		$delimitter = ', ';
		echo $delimitter . $year->name;	
	}
	
	$index++;
}

Cheers

7

Here’s a similar question from last year: http://www.sitepoint.com/forums/showthread.php?665995-how-to-add-commas-and-dashes-for-numbers-ie-1-10-or-1-4-13