Elseif statement failing to execute its assigment

PHP
1 

<?php 
$tac = isset($_GET['subt'])  && is_numeric($_GET['subt'])?$_GET['subt']:null;
$drop = isset($_GET['menu'])  && is_numeric($_GET['menu'])?$_GET['menu']:null;
?>
<?php 
if(($drop != '') && ($tac == 1) || ($drop != '') && ($tac == 2)){
// this is displaying ok.
}
elseif(($drop != '') && ($tac == 3)) {
// this script is displaying ok.
}

  elseif(($tac == 1 ) || ($tac == 2) || ($tac == 3) || ($tac == 5)){

// this is displaying ok as well.
}

elseif($tac == 4){ 
// displaying ok.
}

elseif (($drop != '') && ($tac == 4)) { 
// But then this one is not displaying why? at the moment there is not error displaying in the screen.
// it just display the html code of this condition elseif($tac == 4) 
//instead of the html inside of elseif (($prod != '') && ($cat == 4)) 
//I was wondering since ($tac == 4)  condition is in both elseif statment is getting php confused?  ...

}

The comments are inside the script it self.

help Don’t know what’s really going on.

2

php will only evaluate those expressions until it finds one that is true. Once it does, the remaining expressions are not checked.

elseif ($tac == 4){}
elseif (($drop != ‘’) && ($tac == 4)) {}

So, reorder them.

http://www.php.net/manual/en/control-structures.elseif.php

3

thank you cmalibu.

that made it.