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dimis283 · Nov 6, 2009, 04:54

I am dotin this

Code:

String[] filesToZip ={ args[0]};

but I have this error

Quote:

Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 0

what is wrong

dimis283 · Nov 6, 2009, 05:27

I solve it!

ge0man · Nov 7, 2009, 09:02

This is for anyone else that might get this problem since OP didn;t state what they did to fix it.

Most of the time this error happens when you try to access a spot in the array that wasn't either initialzed or doesn't exist.. for instance.

int [] numberArray = {1,2,3};

the size of the Array is 3...

if you try this: numberArray[3] you will get the above error because you tried to access a spot that was not initialized since there size is 3 and not 4..

this would work:

numberArray[2] which would have the value of 3

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Nov 6, 2009, 05:27	#2
dimis283 SitePoint Evangelist Join Date: Mar 2006 Posts: 581	I solve it!

Nov 7, 2009, 09:02	#3
ge0man SitePoint Member Join Date: Oct 2009 Posts: 14	This is for anyone else that might get this problem since OP didn;t state what they did to fix it. Most of the time this error happens when you try to access a spot in the array that wasn't either initialzed or doesn't exist.. for instance. int [] numberArray = {1,2,3}; the size of the Array is 3... if you try this: numberArray[3] you will get the above error because you tried to access a spot that was not initialized since there size is 3 and not 4.. this would work: numberArray[2] which would have the value of 3