I'm using a jquery paginate method

Code:
$(document).ready(function(){  
  
    var show_per_page = 4;  
    var number_of_items = $('#paginate-content').children().size();  
    var number_of_pages = Math.ceil(number_of_items/show_per_page);  
  
    $('#current_page').val(0);  
    $('#show_per_page').val(show_per_page);  
    
    var navigation_html = '<a id="previous_link" href="javascript:previous();">Prev</a>';  
    var current_link = 0;  
    while(number_of_pages > current_link){  
        navigation_html += '<a class="page_link" href="javascript:go_to_page(' + current_link +')" longdesc="' + current_link +'">'+ (current_link + 1) +'</a>';  
        current_link++;  
    }  
    navigation_html += '<a class="next_link" href="javascript:next();">Next</a>';  
  
    $('#page_navigation').html(navigation_html);  
  
    $('#page_navigation .page_link:first').addClass('active_page');  
  
    $('#paginate-content').children().css('display', 'none');  
  
    $('#paginate-content').children().slice(0, show_per_page).css('display', 'block');  
  
});  
  
function previous(){  
  
    new_page = parseInt($('#current_page').val()) - 1;  
    if($('.active_page').prev('.page_link').length==true){  
        go_to_page(new_page);  
    }  
  
}  
  
function next(){  
    new_page = parseInt($('#current_page').val()) + 1;  
    if($('.active_page').next('.page_link').length==true){  
        go_to_page(new_page);  
    }  
  
}  
function go_to_page(page_num){  
    var show_per_page = parseInt($('#show_per_page').val());  
  
    start_from = page_num * show_per_page;  
  
    end_on = start_from + show_per_page;  
  
    $('#paginate-content').children().css('display', 'none').slice(start_from, end_on).css('display', 'block');  
  
       $('.page_link[longdesc=' + page_num +']').addClass('active_page').siblings('.active_page').removeClass('active_page');  
  
    $('#current_page').val(page_num);  
}
Could I add a line so that the page opens at the top instead of the current scroll level which is near the bottom.