# Thread: Calculate distance with variable lat and lon values

1. ## Calculate distance with variable lat and lon values

Hi

I have a problem with implementing variables into a function that calculate distance between 2 latitudes, longitudes.
One of them is constant, and the second one being passed from the form.

Here is the code:

PHP Code:
``` \$lon1 = \$_POST['lon1'];          \$lat1 = \$_POST['lat1'];          \$lon2 = '-0.30020239';          \$lat2 = '51.58734910';            function distance(\$lat11, \$lon11, \$lat22, \$lon22) {           \$theta = \$lon11 - \$lon22;           \$dist = sin(deg2rad(\$lat11)) * sin(deg2rad(\$lat22)) +  cos(deg2rad(\$lat11)) * cos(deg2rad(\$lat22)) * cos(deg2rad(\$theta));           \$dist = acos(\$dist);           \$dist = rad2deg(\$dist);           \$miles = \$dist * 60 * 1.1515;                  return \$miles;  }  echo "  \$lon1, \$lat1<br>  \$lon2, \$lat2<br>";  //////////  return good calculation  echo distance(52.611644, -0.26304, 51.58734910, -0.30020239) . " miles<br>";  ////////// my way - return wrong calculation   echo distance("\$lon1", "\$lat1", 51.58734910, -0.30020239) . " miles<br>";  ```
As long as i have lat, lon values hardcoded is fine, but idea is to have this calculation done from variables.
Both will vary .... tried different configurations ... i'm losing it ...

How should I code it ??

2. There was a problem in calling a distance() function. Function is defined as lat, lon, lat, lon, but i called it as lon, lat, lon, lat.

Being blind.

SOLVED.

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