using function in the function preg_replace

[fz21z]

Hi
I have a problem, I have two functions tagi() and ObrobkaTekstu. I have not idea how using function tagi in preg_replace in function ObrobkaTekstu().

function tagi($x)
{
  $x=str_replace('<','&lt;',$x);
  $x=str_replace('>','&gt;',$x);
  return $x;
}

function ObrobkaTekstu($tekst_do_obrobki)
{
  $tekst_do_obrobki=preg_replace('{\[code\](.*?)\[/code\]}s','<pre>$1</pre>',$tekst_do_obrobki);
  //....
  return $tekst_do_obrobki;
}

I tried this:

$tekst_do_obrobki=preg_replace('{\[code\](.*?)\[/code\]}s','<pre>'.tagi('$1').'</pre>',$tekst_do_obrobki);

of course this code dosnt work.

Who has idea?

[Pullo]

Hi there,

And welcome to the forums.

the problem with your code is that you cannot pass $1 as a parameter to a function like this, as it would be called before preg_replace is executed.
In this case, you can use preg_replace_callback

This will do what you want:

function tagi($x){
  $x[1]=str_replace('<','&lt;',$x[1]);
  $x[1]=str_replace('>','&gt;',$x[1]);
  return "<pre>$x[1]</pre>";
}
 
function ObrobkaTekstu($tekst_do_obrobki){
  return preg_replace_callback('{\[code\](.*?)\[/code\]}s', "tagi", $tekst_do_obrobki);
}
 
$tekst_do_obrobki = "[code]<hello>SitepointRocks!<goodbye>[/code]";
echo ObrobkaTekstu($tekst_do_obrobki);
?>

This will output:

<pre>&lt;hello&gt;SitepointRocks!&lt;goodbye&gt;</pre>

I hope that helps you.

[fz21z]

Thank you for your help! That's it.