Code:
  Public Function NameIsOnFile($studentname) {
		$sql = "SELECT COUNT(*) FROM studentlist WHERE name = '{$studentname}'";
		$result = mysql_query($sql);
  	        $row = mysql_fetch_array($result, MYSQL_NUM);
		if($row[0] > 0) {			// student name is on file
			return true;
		}
		return false;
	} // end function
Is there an easier / less resource intensive way to accomplish this? (studentid is the key to this table, not name).

I've done a search in this forum, but must not be using the right keywords.

Regards,

grNadpa