I am a newbie to php and have a issue. I have a login code but i need the code to when admin login it sends then to a page with the admin menu bar. When a non admin login it sends them to the same page but with the non admin menu bar.

I have a users table called "teams" with a column name "role" and 1 as admin and 2 as non admin...

Here is my whole login code. Each member has a id so id # 3,15,17 are admin id's and 1,2,4,5,6,7,8,9,10,11,12,3,14,16,18,19,20,21,22,23,24,25,26,27,28,29,30,31 are non admin id;s.. Can anyone help with this code??? Ive tried this ive tried that and i just cant seem to get the dam thing right.

Here is the code:

PHP Code:
<?php  
if(isset($_COOKIE['logged']))  
{  
?>  
<div id='signin'>  

    <form action="http://www.virtualhockeyassociation.com/onlogout.php" method="post" name="logForm" id="logForm" >  
        Welcome <?php session_start(); echo $_SESSION['GM'];?>!  
        <input type="submit" value="Log Out" />  
    </form>  
</div>  
<?php  
}  
if(isset(
$_POST['doLogin']))  
{  
$email=$_POST['usr_email'];  
$password=$_POST['pwd'];  
if(
file_exists('php_classes/config.php'))  
    include_once 
'php_classes/config.php';  
else  
    include_once 
'../php_classes/config.php';  
mysql_connect($dbhost,$dbuser,$dbpass);  
mysql_select_db($dbname);  
echo 
"SELECT * FROM teams where email='$email' and password='$password'";  
$result mysql_query("SELECT * FROM teams where email='$email' and password='$password'");  
mysql_close();  
if(
mysql_num_rows($result) >0)  
{  
    
session_start();  
    
$row=mysql_fetch_array($result);  
    
setcookie('logged',$row['id'],time()+1000);  
    
$_SESSION['uid']=$row['id'];  
    
$_SESSION['GM']=$row['GM'];  
    
$_SESSION['tid']=$row['newsid'];  
    
$_SESSION['teamname']=$row['teamname_l'];  
    
$_SESSION['teamabr']=$row['teamabr'];  
    
header("location: http://www.virtualhockeyassociation.com/teams/teampage_admin.php?id=".$_SESSION['tid']); 
}  
else  
{  
    
header("location: http://www.virtualhockeyassociation.com/index.php?status=loginerror");  
}  
}  
?>  
<div id='signin'>  
                <form action="http://www.virtualhockeyassociation.com/signin.php" method="post" name="logForm" id="logForm" >  
                    <label class='loginLBL' for='username'>USERNAME:</label><input name="usr_email" type="text" class="required" id="txtbox" size="20">  
                    <label class='loginLBL' for='password'>PASSWORD:</label><input name="pwd" type="password" class="required password" id="txtbox" size="25">  
                    <input name="doLogin" type="submit" id="doLogin3" value="Login">  
                </form>  
            </div>
It has to easy. Im missing something but my php verbal knowledge isnt where it needs to be. Im a disabled vet and have taught all i know myself by reading and reading. Problem is part of my disability is a mental, memory thing... Anyway if anyone could show me how and what im doing wrong i would be very greatfull.

Thank you and god bless

~Scott