PHP Code:$query = "SELECT value FROM profile_values where uid= '".$player."' and fid = '12'";
$query_run = mysql_query($query);
if(mysql_num_rows($query_run) >= 1 ){
while($query_row = mysql_fetch_assoc($query_run) ) {
$query_row['value'];
$image = $query_row['value'];
i have wrote this code for image will explainPHP Code:<?php echo '<img src="/'.$image.'" alt="" align = "left" width = "250" height = "250"/>';?>
$image is nothing but a variable to which i have assign database's image value!!!!!
but in my page i can see the image icon not the image plz hemo


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