On my web page, I have a number of buttons. When clicked, a button will load a given XML file. I want to write the output to the same page as the buttons, but I cannot quite make it all work.

I have multiple entries in my XML file, e.g.:
Code XML:
<nation>
	<person>
		<named>Cezanne</named>
		<profession>Artist</profession>
		<work>The Bathers</work>
		<flag>flags/flag_France.gif</flag>
	</person>
	<person>
		<named>Gauguin</named>
		<profession>Artist</profession>
		<work>The Yellow Christ</work>
		<flag>flags/flag_France.gif</flag>
	</person>
</nation>

This javascript function will read and write all tags:
Code JavaScript:
function getTheFile(theFile){ 
			xmlhttp.open("GET",theFile,false);
			xmlhttp.send();
			xmlDoc=xmlhttp.responseXML; 
			/*write to the document, set up a for loop to read and write the xml doc*/
			document.write("<div>");
			var rooty=xmlDoc.getElementsByTagName("person");/*argument passes the root element in xml doc; assigned to variable*/
			for(i=0; i<rooty.length; i++){
				/*write HTML tag: h1*/
				document.write("<h2>");
				/*write named xml tag data into h2 tag*/
				document.write(rooty[i].getElementsByTagName("named")[0].childNodes[0].nodeValue);
				document.write("<img src=");
				document.write(rooty[i].getElementsByTagName("flag")[0].childNodes[0].nodeValue);
				document.write("/>");
				document.write("</h2>"); /*close the h2 tag*/
				document.write("<p>");
				document.write(rooty[i].getElementsByTagName("profession")[0].childNodes[0].nodeValue);
				document.write("<br/>");
				document.write(rooty[i].getElementsByTagName("work")[0].childNodes[0].nodeValue);
				document.write("</p>");
			}
			document.write("</div>");/*close the div tag!!*/
		}

...but the problem is, this basically writes to a whole new page. A user must navigate back to get to the original buttons.

So, I've tried this script:
Code JavaScript:
		function getTheFile(theFile){ 
			xmlhttp.open("GET",theFile,false);
			xmlhttp.send();
			xmlDoc=xmlhttp.responseXML; 
			var rooty=xmlDoc.getElementsByTagName("person");/*argument passes the root element in xml doc; assigned to variable*/
			for(i=0;i<rooty.length; i++){
			/*set variables to hold values of child elements in xml doc*/
			namer=(rooty[i].getElementsByTagName("named")[0].childNodes[0].nodeValue);
			pro=(rooty[i].getElementsByTagName("profession")[0].childNodes[0].nodeValue);
			worker=(rooty[i].getElementsByTagName("work")[0].childNodes[0].nodeValue);
			flagged=(rooty[i].getElementsByTagName("flag")[0].childNodes[0].nodeValue);
			txt="<h1>" + namer + "<img src=" + flagged + "/></h1>Profession: " + pro + "<br />Famous Work: "+ worker;
			document.getElementById("showGuy").innerHTML=txt;
			}
		}

...which keeps the user on the same page, but only the last XML entry is written to the page.

I see that I need to write a variable to a page element to stay on the page, but somehow that variable needs to hold lots of data. I tried another for loop within the first for loop, but that didn't work.

Can anyone point me in the right direction? Thanks in advance!