Hello,

I am trying to implement a jquery technique and am having a problem.

The script produces a select drop down list for a 3 character language code with the last value as other. When other is selected, jquery should show a div that allows a user to input a new language code.

After selecting other, the div is not showing.

Can someone take a look at this?

Also, when coding jquery, should the coding include separate script tags for each of the functions which means calling the
Code:
$(document).ready(function()
again or is it better to combine them all under one set of script tags?
e.g. tooltips are separated from the hide/show below.

Thanks,

Peter

Code:
<script src="jquery.tools.min.js" type="text/javascript"></script>
<!-- jquery tooltips  -->
<script type="text/javascript">
$(document).ready(function(){
    // specifies div name, element[part of element]
    //$("#dyna textarea[title]").tooltip({
    $("#tips a[title]").tooltip({
        position: "center right",
        track: true, 
        predelay: 10,
        delay: 50, 
        showURL: false, 
        offset: [5, 0],
        effect: "fade",
        fadeInSpeed: 400,
        fadeOutSpeed: 200,
        opacity: 0.9
    });
    $(this).hide("slow");

});
</script>

<script type="text/javascript" >
// for hide - display field based on select
$(document).ready(function() {
  $.viewInput = {
    '0' : $([]),
    //THIS IS THE NAME OF THE DIV WRAPPING THE HIDDEN FIELD
    'otherField' : $('#otherField'),
  };

$('#101').change(function() {
    // HIDES THE INPUT FIELD IF ANOTHER DROPDOWN ITEM IS SELECTED ONCE THE HIDDEN FIELD IS LOADED
    $.each($.viewInput, function() { this.hide(); });
    // SHOWS THE INPUT FIELD ITEM IF SELECTED
    $.viewInput[$(this).val()].show();
  });

});
</script>


if ($key == "101"){
print ("<div id=\"$key\">\n");  // for hide - display field based on select

// language display values
$select = "SELECT distinct lang FROM $db_name.$table_name order by lang";
$result = mysql_query($select) or die($errorinfo6);

// do select
print "<select id=\"$key\" name=\"$key\" value=\"$value\" class=\"dropdown\" 
title=\"use <b>other</b> to add new item\" \"> ";

// default empty to avoid user confusion
print '<option value=""></option>';

// populate drop down with values
while($row = mysql_fetch_assoc($result)) { 
if( empty($row["lang"]) ) continue;  // because nulls currently exist
    print '<option value="'.$row["lang"].'">'.$row["lang"].'</option>';
}

// do input
print "<option value=\"otherField\"><b>Other</b></option>";
print "</select>

<div id=\"otherField\">
<input type=\"text\" id=\"$key\" name=\"$key\" size=\"3\" value=\"$value\"  class=\"textfield\" />
</div>";

//print '</select>';
print '</div>'."\n";
}