Hi,
The below code produces an error. I am just testing some stuff, please don't try to find sense in it.
The error is triggered in arg2, on the line where you can find data3
I can't seem to find what is wrong...
Thanks in advance for your help.PHP Code:$obj
->arg1(array(
'data1' => 'id',
'data2' => 'path',
'data3' => $tableName,
'data4' => array(
'foo' => 'var',
),
'data5' => array(
'foo' => 'var',
),
)
)
->arg2(array(
'data1' => 'id',
'data2' => 'path',
'data3' => array(
array(
'table' => 'name',
'col' => 'name',
'pk' => 'pk',
),
//goes on......
Regards,
-jj.![]()




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