How to remove newlines with ereg and hex value?

[Bitmesh]

I need to remove newlines from a string using the hex value for newline. The string may contain "\n", and I do not want to remove those, only newlines in the string. For instance, this is my string:

Hello


World\n\nHow are you today?

How would I remove the newlines under "Hello" while leaving the "\n" in tact after "World"? I figured I could use the hex value of NL, but this does not work:

echo ereg_replace("\x0A", ' ', $string);

It just returns the original string with the newlines after "Hello" in tact. Any ideas?

Thanks,
Nathan

[Bitmesh]

I figured it out. This is the code I used:

echo preg_replace("/[\n\r]/", '', $string);

The \n's won't be removed unless I use \\n.

[Ernie1]

Yeah
Part of a pattern that is in square brackets is called a "character class".
In a character class the only meta-characters are:

\ general escape character
^ negate the class, but only if the first character
- indicates character range
] terminates the character class