Passing a function variable to another function

[JREAM]

Hey guys.
I hope I can reply if someone is able to answer me, my dad might turn off the internet in a little bit.

I was wondering this.
is there a way to do that and pass the hey() variable into the say()?

function hey () {
$hey = '1';
}

function say() {
echo hey() . ' test';
} 

I dont understand what return does, i tried return $hey.
I own a php manual but can not solve this.
Thank you

[UFTimmy]

return is what you're looking for.

function hey () {
$hey = '1';
return $hey;
}

function say() {
echo hey() . ' test';
} 

[spiderling]

You have to call say() so it can call hey(), and yes use return in hey().

[logic_earth]

PHP 5.3 Coolness

function hey () {
    $hey = '1';
    return function () use ( $hey ) {
        echo $hey, ' test';
    };
};

$say = hey();
$say(); 

[JREAM]

Ok I understand thank you for this reply guys, i can play with this more and understand thing now thanks

ps: that 5.3 php is very cool