# Thread: Help Needed - Only "basic" PHP required.

1. ## Help Needed - Only "basic" PHP required.

Hi All,

I've just started a class on PHP for my TAFE course and I'm stuck already. We haven't done much PHP as of yet - learnt about if/else statements, switch statements and some loops but that is all. Now I have a task to do involving determining whether a year is a leap year or not. It does not have user input, just declare \$year inside the code.

I've been able to determine whether \$year is a leap year when dividing by 4 but am unable to take it more advanced. Part A said to use if/else statements. This is part b (which I'm stuck on):

If a year is evenly divisible by 4, it is a leap year, unless it is divisible by 100. if it is divisible by 100, it is not a leap year unless it is also evenly divisible by 400. if the year is not a leap year, print the number of years to the next leap year.

Anyone have any suggestions?

Thanks.

2. to find the next leap year, when you find one it is simple as adding 4.
PHP Code:
``` var_dump( 2008 + 4 );  ```

3. Were you taught about the modulus operator? If so, I bet they want to see you use that here.
Code:
```if ((\$number &#37; 100) == 0) {
// evenly divisible by 100
}```

4. Originally Posted by crmalibu
Were you taught about the modulus operator? If so, I bet they want to see you use that here.
Code:
```if ((\$number % 100) == 0) {
// evenly divisible by 100
}```
yeah we were taught about the modulus operator. I just don't know how to put all of it together.

5. to determine whether a year is a leap year or not , following are algorithms and pseudo code . hope this gives better understanding !

if year modulo 400 is 0 then leap
else if year modulo 100 is 0 then no_leap
else if year modulo 4 is 0 then leap
else no_leap

A more direct algorithm (terms may be grouped either way):

function isLeapYear (year):
if ((year modulo 4 is 0) and (year modulo 100 is not 0)) or (year modulo 400 is 0)
then true
else false

6. Originally Posted by hiddenpearls
to determine whether a year is a leap year or not , following are algorithms and pseudo code . hope this gives better understanding !

if year modulo 400 is 0 then leap
else if year modulo 100 is 0 then no_leap
else if year modulo 4 is 0 then leap
else no_leap

A more direct algorithm (terms may be grouped either way):

function isLeapYear (year):
if ((year modulo 4 is 0) and (year modulo 100 is not 0)) or (year modulo 400 is 0)
then true
else false
Just want to polish your pseudo-code .Make sure there is odd number of truth condition. btw % is very important operator.

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