if (!$foo && !bar) actually won't gave error when $bar is typed as bar
the statement
if (!$foo && !$bar) { echo 'hi'; }
is typed as
if (!$foo && !bar) { echo 'hi'; }
(with the '$bar' mistyped as 'bar')
and i just found that PHP won't give error... is it true that the word bar is taken as a string literal... it seems a bit weird and sometimes it can give hard to catch error. many thanks.
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