help to correct syntax

[runrunforest]

"SELECT a.* 
			, b.thumb_id
			, c.amount 
			, ( SELECT COUNT(*)
        		FROM listing_bid 
      		 	WHERE listing_id = a.id ) AS c_rows	
		FROM listing a
		LEFT OUTER 
		JOIN listing_photo b
		  ON b.listing_id = a.id
		 AND b.key = 1
		LEFT OUTER
		JOIN listing_bid c
		  ON c.listing_id = a.id ORDER BY c.id DESC LIMIT 1
	   WHERE a.activation = 1 ";

I want to get the highest amount so I put the ORDER BY clause in, its error.

So I need help to put the ODER clause correctly in the query.

[r937]

write this down somewhere --

SELECT
FROM
[ WHERE ]
[ GROUP BY ]
[ HAVING ]
[ ORDER BY ]

[runrunforest]

In the query you have built before. I want one more thing.

Get the highest amount (only one) in table listing_bid, the highest amount will correspond with the the highest listing_bid.id

The possible WHERE clause is WHERE listing_bid.id = a.id

This is what I come up with, but its not working. Please help me fix it!

"SELECT a.* 
			, b.thumb_id
			, c1.amount AS amount1
			, ( SELECT COUNT(*)
        		FROM listing_bid
      		 	WHERE listing_id = a.id ) AS c_rows
			, ( SELECT amount 
			    FROM listing_bid 
			    WHERE listing_id = a.id ORDER BY id DESC LIMIT 1  ) AS h_amount
		FROM listing a
		LEFT OUTER 
		JOIN listing_photo b
		  ON b.listing_id = a.id
		 AND b.key = 1
		LEFT OUTER
		JOIN listing_bid c1
		  ON c1.listing_id = a.id
	   WHERE a.activation = 1"

[runrunforest]

So weird! its working now.

But can you tell me if I am doing it absolutely coreectly