Send array to another page.How?

[ramki067]

HI,
I have a javascript array which i need to pass to another page and access this array using PHP code. I've written the javascript code but need your help on this to send the array to another page. Am i doing anything wrong?Any ideas?

function check()
{

var frm=document.forms.stream_selection
sel_num = new Array()
for(j=1;j<=1000;j++)
{
  if(!frm[j].checked)
  {
      frm[0].checked=false
  }
  else
  {
	 sel_num =frm[j].value
	 	 
	Parr = new Array();
	for(i=0 ;i<sel_num.length ;i++){
		Parr.push(escape(sel_num[i].innerHTML));
	}
	location.href="selected_streams.php?arr="+Parr
	
  }

	var par = new Array();
	par = get_paragraphs();
	
	var parString = par.toString();
	
}

}

Thanks,
Ramki.

[Mittineague]

If the form is the POST method, arrays like
<input name="array_name[]" ...
are passed to the "action" file as $_POST['array_name']

[ramki067]

If the form is the POST method, arrays like
<input name="array_name[]" ...
are passed to the "action" file as $_POST['array_name']

Thanks. But i'm using javascript to send an array to next page. But i'm unable to access the array in the next page. Infact, i've even given an alert just before the href line as shown below but the alert never executes. What could be the reason?

function check()
{
alert('1');
var frm=document.forms.stream_selection
sel_num = new Array();
Parr = new Array();
for(j=1;j<=500;j++)
{
  if(!frm[j].checked)
  {
      frm[0].checked=false
  }
  else
  {
	Parr.push(j);
  }
  
}
alert('3');
ParrStr=Parr.join(','); 
location.href="selected_streams.php?arr="+ParrStr;

}

and in retreiving form my code is :

$sel_numbers=$_POST['arr'];
$sel_num=split(",", $sel_numbers);
//$sel_num = explode(" ", $sel_numbers);

$i=0;
while ($i < count($sel_num)) 
{
   //echo "$all_streams[$i]<br>";
   echo "$sel_num[$i]<br>";
   $i++;
}

Thanks,
Ramki.

[Mittineague]

If the alert that's inside the check() function isn't showing then the function isn't getting entered. I imagine it's getting called from the form somehow?
Please post the pertinent form code.
And it may help to var_dump() the POST array to see what it looks like. ie.

var_dump($_POST['arr']);
$sel_numbers=$_POST['arr']; 

[ramki067]

If the alert that's inside the check() function isn't showing then the function isn't getting entered. I imagine it's getting called from the form somehow?
Please post the pertinent form code.
And it may help to var_dump() the POST array to see what it looks like. ie.

var_dump($_POST['arr']);
$sel_numbers=$_POST['arr']; 

Alerts('1'), and another alert which i had placed inside the else loop also popped up, but the alert('3') didn't! I really don't know why is this happening. Can u help.

Regards,
Ramki.

[Mittineague]

What browser/version are you using? Some (older) browsers don't support push().
Try this (don't use 500)

for(j=1;j<=5;j++)
{
  if(!frm[j].checked)
  {
alert("frm[" + j +"] not checked");
      frm[0].checked=false;//added missing semi-colon
  }
  else
  {
alert("before push " + j);
	Parr.push(j);
alert("after " + j);
  }
  
}