can it be done in PHP

[RJweb]

allternating color rows in a table, I know it can be done with javascript, but was wondering if all so be done in PHP, thx in advance

[Ernie1]

try this

[wheeler]

function bgcolor()
{
    global $bgcolor;
    
    if ($bgcolor == 'white') {
        $bgcolor = 'gray';
    } else {
        $bgcolor = 'white';
    }
    
    echo 'class="'.$bgcolor.'"';
    
}

while ($row = mysql_fetch_array($query))
{
echo "<tr " . bgcolor() . ">";
echo "<td>&nbsp;</td>";
echo "</tr>";
} 

god damn asp is ugly!

[CommanderZ]

$even=true;
while ($row = mysql_fetch_array($query))
{
echo "<tr bgcolor=".$even?"white":"gray".">";
echo "<td>&nbsp;</td>";
echo "</tr>";
$even!=$even;
}

[BluDragon]

$i = 0;
while ($row = mysql_fetch_array($query))
{
  if ($i % 2)
    $bgcolor = "white";
  else
    $bgcolor = "gray";

echo '<tr bgcolor="'.$bgcolor.'">';
echo "<td>&nbsp;</td>";
echo "</tr>";

  $i++;
} 

Should be percent not 37.

[Grumps]

just make a loop. Let say you're getting your stuff from database.

using while loop

echo "<table>";
$i=0
// this is a while loop
while () {
    // if the remainder of $i divided by 2 is equals to zero
    if ($i&#37;2==0) {
        echo "<tr><td></td></tr>";
    } else {
        echo "<tr style='background:#000;'><td></td></tr>";
    }
    // increases $i indicator
    $i++;
}
echo "</table>"; 

[BluDragon]

$i = 0;
while ($row = mysql_fetch_array($query))
{
  if ($i % 2) // i percent two
    $bgcolor = "white";
  else
    $bgcolor = "gray";

echo '<tr bgcolor="'.$bgcolor.'">';
echo "<td>&nbsp;</td>";
echo "</tr>";

  $i++;
}