Getting Domain Name Extension

[mrmbarnes]

Hi All

I need to get the domain name extension of a domain name.

Example:

whatever.com = .com

whatever.com.au = .com.au

whatever.net = .net

I have no idea how to do this and have spent almost an hour trawling the forums trying to work it out.

Any help would be great.

Thanks

[logic_earth]

a better means then using $parts[count($parts)-1];
would be to use end()

$parts = split('.', $domain);
$ext = end($parts);

# Or

$ext = end(split('.', $domain)); 

[r937]

how do you know when you want the TLD only (e.g. .com) and when you want both the top and second level domain (e.g. .com.au, .co.uk)?

how would you code for that?

[felgall]

Presumably if the length of the TLD is 2 (country specific) you want the SLDL as well but if the length of the TLD is between 3 and 7 you only want that.

[byron3@earthlink]

$url[0] = "http://www.mydomain.info/anydirectory/valid.php";
$url[1] = "http://www.mydomain.org";
$url[2] = "homepage.com/test.php";
$url[3] = "homepage.gov";


function getURLExtension( $url ) {
    $url = ltrim( $url, "http://" );
    $parts = explode( "/", $url );
    $tmp = explode( ".", $parts[0] );
    
    if ( count ( $tmp ) >= 3 ) {
        return $tmp[2];
    } else {
        if ( count ( $tmp ) == 2 ) {
                return $tmp[1];
        }
    }
    return FALSE;
}
 
foreach ( $url as $K ) {
    echo "The url extension is : " .getURLExtension( $K ). "<br>\n";
} 

Yields :
The url extension is : info
The url extension is : org
The url extension is : com
The url extension is : gov

[logic_earth]

So something like this?

<?php

function getDomainTld ($domain) {

    $parts = explode('.', $domain);
    $tld   = array_pop($parts);

    if (strlen($tld) < 3) {
        $tld = end($parts) . '.' . $tld;
    }

    return $tld;

}


$domain = 'www.example.com';
$domain = 'www.example.co.uk';

print getDomainTld($domain); # co.uk

[logic_earth]

With the previous posters code (byron3) combined it and mine togeather.

<?php
 
function getDomainHost ($url) {
 
    $url = strtolower($url);
 
    if (strstr($url, '://') !== false) {
 
        $url = parse_url($url);
        return $url['host']; # PHP5: return parse_url($url, PHP_URL_HOST);

    }
 
    $parts = explode('/', $url);
    return $parts[0];
 
}
 
function getDomainTld ($domain) {
 
    $domain = getDomainHost($domain);
 
    $parts = explode('.', $domain);
    $tld   = array_pop($parts);
 
    if (strlen($tld) < 3) {
        $tld = end($parts) . '.' . $tld;
    }
 
    return $tld;
 
}
 
$url[0] = 'http://www.mydomain.info/anydirectory/valid.php';
$url[1] = 'http://www.mydomain.co.uk';
$url[2] = 'homepage.com/test.php';
$url[3] = 'homepage.gov';
$url[4] = 'ftp://www.mydomain.com/valid.php';
 
 
foreach ($url as $K) {
    echo getDomainTld($K) . "<br>\n";
}

It also correctly returns co.uk

[r937]

Presumably if the length of the TLD is 2 (country specific) you want the SLDL as well

that would be wrong for most .ca sites, including mine

[logic_earth]

One will probably need a list of all variations on TLDs but thats too bother guess having the end (.uk, .ca) is the best we can get.

Or might mod the if statement in getDomainTld to:

if (strlen($tld) < 3 && ($tmp = end($parts)) == 'co') {
    $tld = $tmp . '.' . $tld;
}

[Dan Grossman]

...and .tv, .us, .ws, .to...

You could always stick all the top level domains you want to match in an array and check if they're the end of the domain string.