this is my error note: the while line is line 14Code MySQL:$result2 = mysql_query("SELECT * FROM postjobs WHERE title='$id'"); echo "<center>"; echo "<table border='0'> <td> <th>No. </th> <th>Job Titles </th> </tr>"; while($row2 = mysql_fetch_array($result2)) ------> error line { echo '<tr>'; echo '<td>' . $row['user'] . '</td>'; echo '<td>' . $row['title'] . '</td>'; echo '</tr>'; } echo "</table>"; echo "</center>";
Warning: Supplied argument is not a valid MySQL result resource in c:\apache\htdocs\gp1\ps.php on line 14




Bookmarks