Trying to construct a JS line in PHP, problem...

[Rob_H]

Hi All,

I'm trying to construct a simple Javascript line (used in a swap image) using PHP. Here it is:

<a href="javascript:;" onclick="MM_swapImage('bigimage','','<?php $this->absolute_path . 'images/large/' . $vehicle['int_main'];?>',1)">

So this, I'd hoped, would fill in the value of the image to be swapped with from a DB call earlier on.

The contructed line looks like this:

<a href="javascript;:" onclick="MM_swapImage('bigimage','','',1)"> 

It should look like this:

<a href="javascript;:" onclick="MM_swapImage('bigimage','','images/large/dsc_3647.jpg',1)"> 

I know $this->absolute_path . 'images/large/' . $vehicle['int_main'] produces the right code (an image name) and the JS swap image works but simply inserts a blank because there's no image to swap with i.e. it is missing in the JS line? I'm all out of ideas now, anyone offer some insight?

Many thanks

Rob

[Dan Grossman]

You're missing the word "echo" to tell it you want to output that variable.

<a href="javascript:;" onclick="MM_swapImage('bigimage','','<?php echo $this->absolute_path . 'images/large/' . $vehicle['int_main'];?>',1)">

[Rob_H]

Such a simple error, sometimes I cannot see the wood for the trees!!!

Thank you